How to iterate with fsolve to find Mach number

I'm trying to interate static pressure ratio to find Mach number using fsolve, but I can't get the syntax correct. The Mathworks explaination didn't really help me. Could anyone out there help?
I have a set range for the pressure ratio, but the Mach number is unknown. Here is the equation:
Capture.PNG
This is what I have so far for the code:
pt2pinf = [1.9, 2.7, 3.5, 4.3, 5.1, 5.9, 6.7, 7.5, 27.5, 47.5, 67.5 ,87.5 ,107.5,127.5, 147.5, 200, 252.5, 305, 357.5, 410, 462.5 ,515 ,567.5, 620, 672.5, 725, 777.5, 830 ,882.5, 935, 987.5, 1000];
Me0=ones(1,32);
g=1.2;
pt2pinf_test = fsolve(@(Me)(((1+((g-1)/2)*Me.^2)^(g/(g-1)))/((((2*g)/(g+1))*Me.^2)-((g-1)/(g+1)))),Me0);

8 Comments

Torsten
Torsten on 10 Sep 2019
Edited: Torsten on 10 Sep 2019
In the function you passed to "fsolve", you forgot to subtract the pressure ratio.
And for all ^, / and * operators, use .^, ./ and .* (elementwise operation).
So it should look like this? But I get an error doing this. I'm sorry, I'm still confused. Because I have Me0 set as ones, should it be zeros while fsolve is trying to solve the problem?
pt2pinf_test = fsolve(@(Me)((((1+((g-1)/2).*Me.^2)^(g/(g-1)))/((((2*g)/(g+1)).*Me.^2)-((g-1)/(g+1))))-pt2pinf),Me0);
You did not substitute all ^ by .^ and all / by ./ .
I'm getting this, but I have the same array size:
Equation solved, fsolve stalled.
fsolve stopped because the relative size of the current step is less than the
value of the step size tolerance squared and the vector of function values
is near zero as measured by the value of the function tolerance.
<stopping criteria details>
Thus you were successful.
Hailey
Hailey on 10 Sep 2019
Edited: Hailey on 10 Sep 2019
But I need to have the Mach number values. I need an array of Mach numbers that match up with it's respective pressure ratio value. This did not do that.
They are stored in the fsolve return parameter (pt2pinf_test in your case).
Hailey
Hailey on 10 Sep 2019
Edited: Hailey on 10 Sep 2019
The values are too small to be a Mach number after a shock wave.
Not sure what I did wrong.

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 Accepted Answer

Torsten
Torsten on 10 Sep 2019
Edited: Torsten on 10 Sep 2019
function main
pt2pinf = [1.9, 2.7, 3.5, 4.3, 5.1, 5.9, 6.7, 7.5, 27.5, 47.5, 67.5 ,87.5 ,107.5,127.5, 147.5, 200, 252.5, 305, 357.5, 410, 462.5 ,515 ,567.5, 620, 672.5, 725, 777.5, 830 ,882.5, 935, 987.5, 1000];
Me0 = 5.0;
g = 1.2;
fun = @(Me,pquot)((((1+((g-1)/2)*Me.^2).^(g/(g-1)))./((((2*g)/(g+1))*Me.^2)-((g-1)/(g+1))))-pquot).^2
for i = 1:numel(pt2pinf)
pquot = pt2pinf(i);
machnumber(i) = fminsearch(@(Me)fun(Me,pquot),Me0,optimset('TolFun',1e-10));
end
machnumber
fun(machnumber,pt2pinf)
end

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Asked:

on 10 Sep 2019

Edited:

on 10 Sep 2019

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