# how to make heatmap have a square-shape?

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kinger on 13 Sep 2019
Answered: Ramy Rabie on 6 Jun 2020
when I do
a=rand(4);
heatmap(a);
I got the following image: How can I make the figure to a square-shaped one? I tried to use
axis equal;
but there's an error: Using axis with heatmap is not supported.
It seems that "axis" is not supported in heatmap.
darova on 13 Sep 2019

Shubh Sahu on 17 Sep 2019
Hello Kinger,
heatmap does not support axis command directly but by extracting properties of heatmap, square-shaped figure can be made.
a=rand(4);
k=heatmap(a);
k.positions=[0.1300 0.1100 0.7179 0.179];
While using above code, make sure that Units property is set to normalized.
Regards,
Shubh
kinger on 17 Jan 2020

Ramy Rabie on 6 Jun 2020
x = [zeros(11,1), 6*ones(11,1) , 137*ones(11,1) ,...
84*ones(11,1) ,9*ones(11,1) ,4*ones(11,1)]
y = [ ones(1,6) ; 4*ones(1,6) ; 45*ones(1,6) ;...
25*ones(1,6) ; 2*ones(1,6) ; 2*ones(1,6) ;...
13*ones(1,6) ; 52*ones(1,6) ; 58*ones(1,6) ;...
15*ones(1,6) ; 4*ones(1,6)]
% Making Heatmap figure has square tiles
wposX=100; wposY = 100;
heatmapLength = 500;
heatmapWidth = heatmapLength - (size(y,2)/size(y,1))*heatmapLength;
figure('Renderer', 'painters', 'Position', [wposX wposY heatmapWidth heatmapLength])
tempMap = heatmap(x+y);
% Make heatmap fill the figure
tempMap.InnerPosition = [0 0 1 1];