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How to find minimum number of largest square of 1 in an 2D bool matrix

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raym
raym on 19 Oct 2019
Answered: Walter Roberson on 20 Oct 2019
I have a 2D bool image (dimension 81x65) with several irregular regions black(mainly in the middle) and other pixes white(mainly in the outer part).
Is there a way to split the white region into square pieces as large as possible, and get the position and size for each square?
Thanks.
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raym
raym on 20 Oct 2019

The square can be any size and with different sizes. The key is to split white pixels into less squares, so some of the square should have large area.

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Accepted Answer

Walter Roberson
Walter Roberson on 20 Oct 2019
D = bwdistgeodesic(logical(YourImage), ~YourImage);
Now iterate. if there are no finite values in D, break the loop. Find the largest value in D. It is at the corner of a square of white pixels of that dimension, but you will need to do a little work to figure out which corner it is. When you have figured out which corner it is, record that square location and then set all the D locations inside that square to be inf or nan. Now return back to the beginning of the loop (looking for the largest remaining value)
This is a "greedy" algorithm. It makes no attempt at all to be consistent in block sizes. If there were a situation in which two squares of equal size plus one small square would cover a section, then the algorithm would instead take the larger square leaving the rest to be broken up into a number of smaller squares.

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