# Storing values in a loop

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Prince Igweze on 7 Nov 2019
Edited: Stephen Cobeldick on 7 Nov 2019
t = linspace(10^-4,10^12,17)
q = zeros(length(t),1);
for i = 1:17
m(i) = inv((At * Cd * A) + (t(i) * Ht * H)) * At * Cd * do
end
how can i store the values in this loop
m is a 50 by 1 matrix
Note that all the variable in the equation are also matrixes
Shows this when i try running it
Unable to perform assignment because the left and right sides have a different number of elements.

Shubham Gupta on 7 Nov 2019
Note that all the variable in the equation are also matrixes
What is the dimension for the right side matrix? I am guessing it is not (1x1) dimensional matrix otherwise it would have worked, since left side is of 1x1 dimesion.
But you can use cell type array to do this kind of assignment:
t = linspace(10^-4,10^12,17);
q = zeros(length(t),1);
m{1,17} = {}; % predefine cell vector m of dimesion 1x17
for i = 1:17
m{i} = inv((At * Cd * A) + (t(i) * Ht * H)) * At * Cd * do; % note m{i} is used instead of usual m(i)
end
Let me know if you have doubts !
Stephen Cobeldick on 7 Nov 2019
To make your code more efficient and robust you should probably be using mldivide instead of inv and *. Explicit matrix inversion is rarely required (because there are better methods for solving such systems of equations).