Please any help.
Calculating a surface integral over a regular shape
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Oussama GASSAB
on 22 Nov 2019
Edited: Oussama GASSAB
on 24 Nov 2019
let's suppose a function given in polar coordinate F(r,phi) and our purpose is to calculate the surface integral, say F(r,phi)dA over the region S defined by
S={ |Z|<b , |z-z0|>a } where Z=r*exp(1j*phi). it means the regions between the circles |Z|=b , |z-z0|=a . However, F(r,phi) has singularities inside the circle |z-z0|=a . therefore, we are not able to use integral(over circle |Z|<b )-integral(over circle |z-z0|<a) .
your help and consideration are much appreciated.
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David Goodmanson
on 24 Nov 2019
Hi Oussama,
I am assuming that z and Z are basically the same thing, is that correct? Are z0 and 'a' such that the 'a' circle is totally contained in the b circle? Or the other way round? Is z0 real, or can it be complex?
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