Concatenation error during frequency response analysis

1 view (last 30 days)
So I have a system that I'm trying to run frequency response analysis on manually through Matlab, but part way through my code I get a concatenation error and I'm not sure why Matlab is even concatenating in the first place. Can anyone help? Thanks!
I6 = 3;
L = 0.5;
I3 = 1.2 * I6;
f_n = 1;
k = I3*(2*pi()*f_n)^2;
C2 = 1/k;
C8 = -9.81;
I9 = (I6*L^2)/12;
H = L^2*I3*I9+L^2*I6*I9-4*I3*I6;
omega = [0:0.001:2*pi()];
S = i*omega;
X = det([0 -1/I3 0 0; (H-L^2*I9)/(H) S (2*L^2*I3*I6)/(H*C8) 0; 0 0 S -1/I9; -(2*L*I9)/H 0 -(2*L*I3*I6+H)/(H*C8) S]);
Theta = det([S -1/I3 0 0; (L^2*I6*I9)/(H*C2) S (H-L^2*I9)/H 0; 0 0 0 -1/I9; -(2*L*I6*I9)/(H*C2) 0 -(2*L*I9)/H S]);
F_in = det([0 -1/I3 0 0; (L^2*I6*I9)/(H*C2) S (2*L^2*I3*I6)/(H*C8) 0; 0 0 S -1/I9; -(2*L*I6*I9)/(H*C2) 0 -(2*L*I3*I6+H)/(H*C8) S]);
ANS1 = abs(X/F_in)
ANS2 = abs(Theta/F_in)

Accepted Answer

Turlough Hughes
Turlough Hughes on 25 Nov 2019
Edited: Turlough Hughes on 25 Nov 2019
Your problem is in these lines because S has 6284 elements:
X = det([0 -1/I3 0 0; (H-L^2*I9)/(H) S (2*L^2*I3*I6)/(H*C8) 0; 0 0 S -1/I9; -(2*L*I9)/H 0 -(2*L*I3*I6+H)/(H*C8) S]);
Theta = det([S -1/I3 0 0; (L^2*I6*I9)/(H*C2) S (H-L^2*I9)/H 0; 0 0 0 -1/I9; -(2*L*I6*I9)/(H*C2) 0 -(2*L*I9)/H S]);
F_in = det([0 -1/I3 0 0; (L^2*I6*I9)/(H*C2) S (2*L^2*I3*I6)/(H*C8) 0; 0 0 S -1/I9; -(2*L*I6*I9)/(H*C2) 0 -(2*L*I3*I6+H)/(H*C8) S]);
I suspect the following is what you need:
I6 = 3;
L = 0.5;
I3 = 1.2 * I6;
f_n = 1;
k = I3*(2*pi()*f_n)^2;
C2 = 1/k;
C8 = -9.81;
I9 = (I6*L^2)/12;
H = L^2*I3*I9+L^2*I6*I9-4*I3*I6;
omega = [0:0.001:2*pi()];
S = i*omega;
X=nan(size(S));Theta=nan(size(S)); F_in=nan(size(S));
for c=1:length(S)
X(c) = det([0 -1/I3 0 0; (H-L^2*I9)/(H) S(c) (2*L^2*I3*I6)/(H*C8) 0; 0 0 S(c) -1/I9; -(2*L*I9)/H 0 -(2*L*I3*I6+H)/(H*C8) S(c)]);
Theta(c) = det([S(c) -1/I3 0 0; (L^2*I6*I9)/(H*C2) S(c) (H-L^2*I9)/H 0; 0 0 0 -1/I9; -(2*L*I6*I9)/(H*C2) 0 -(2*L*I9)/H S(c)]);
F_in(c) = det([0 -1/I3 0 0; (L^2*I6*I9)/(H*C2) S(c) (2*L^2*I3*I6)/(H*C8) 0; 0 0 S(c) -1/I9; -(2*L*I6*I9)/(H*C2) 0 -(2*L*I3*I6+H)/(H*C8) S(c)]);
end
ANS1 = abs(X./F_in)
ANS2 = abs(Theta./F_in)
  1 Comment
Michael Gibson
Michael Gibson on 25 Nov 2019
Oh. I feel stupid now. I've used for loops in that fashion multiple times in the past month. Why didn't that occur to me?
Thanks for the help!

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!