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Fitting data using polyfit, nlfit ?

Asked by Ganesh
on 1 Oct 2012

I have 2 sets of data of the same size (X1, Y1) and (X2,Y2). (X1,Y1) has a linear relationship with zero intercept (Y1=slope*X1). How can I estimate the slope, R^2 value and plot it along with 95% confidence interval lines? Using Corrcoeff, polyfit and polyval gives me a relationship of the form Y1=slope*X1 + c, but I would like to force c=0.

(X2,Y2) has a non-linear relationship of the form Y2=A-Bexp(C*X2). Likewise, I would like to determine A,B & C along with R^2 value and plot it along with 95% confidence interval lines. I know I have to use nlinfit, nlparci but I am new in this and would need your help.

Thanks much.


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1 Answer

Answer by Star Strider
on 1 Oct 2012
Edited by Star Strider
on 1 Oct 2012
 Accepted Answer

You seem to be acquainted with nlinfit and know how to use it, but apparently not with Anonymous Functions.

I suggest you use nlinfit for both problems. With B = [B(1) ... B(n)]' a column vector of parameters, your Y1 function becomes:

Y1 = @(B,x) B.*x;

since with only one parameter in it, you do not need to use subscripts.

Your Y2 function becomes:

Y2 = @(B,x) B(1)-B(2).*exp(B(3).*x); 

These should work as your modelfun functions in nlinfit.


Thank you for providing with the code. It ran smoothly. The only change I made is in the plot command. F2_est is a row array, while FitCI95 is a column array. So, I made a minor change as: plot(X2fit, F2_est'-FitCI95+0.01, ':r', 'LineWidth', 1.5) plot(X2fit, F2_est'+FitCI95, ':r', 'LineWidth', 1.5)

Thanks a ton for your help.

Is there a way to find the R^2 value for the fit?

R^2: Yes, if you use the NonLinearModel class, particularly That will also give you a number of other statistics. I use it occasionally when I need the extra statistics it gives. There is a link to NonLinearModel at the end of the nlinfit documentation.

It is my pleasure to help!

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