How to display two things on one line?

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My assignmend is telling me to use the display command to display the phrase "The first random variable is" and the x value (calculated earlier in the script) on the same line. The result should be:
The first random variable is 4
Not:
The first random variable is
4
Heres the code (don't worry about the y value)
x=ceil(5*rand(1));
y=floor(99*rand(1));
disp("The first number is ")
disp(x)
  2 Comments
per isakson
per isakson on 15 Jan 2020
Edited: per isakson on 15 Jan 2020
Homework I assume.
You have to do it with one disp() statement, because disp() automatically adds a newline after the output
Image Analyst
Image Analyst on 15 Jan 2020
Or use fprintf() like I show in my Answer below.

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Accepted Answer

Image Analyst
Image Analyst on 15 Jan 2020
Use fprintf():
fprintf('The first random variable is %d.\n', x);

More Answers (2)

per isakson
per isakson on 15 Jan 2020
Edited: per isakson on 16 Jan 2020
See Append Text to Strings before you try my code.
>> "abc"+"def"
ans =
"abcdef"
>>
and your example
>> x = 17;
>> disp( "The first number is " + num2str(x) )
The first number is 17
it's even possible to add the numerical x to the string.
>> disp("The first number is " + x )
The first number is 17
The doc on plus, + Addition says
If one input is a string array, then the other input can be a numeric, logical, character, string, or cell array.
>> "true is displayed as "+true
ans =
"true is displayed as true"

Paul
Paul on 3 Mar 2023
Would this be considered a character array or string? I need to output text without using either...
disp("The original number was "+integer+" and the flipped number is "+flipped)
  3 Comments
Walter Roberson
Walter Roberson on 3 Mar 2023
If the point is that the output must not have the quotation marks, then disp() should work for that purpose.
But I suspect that the restriction is hinting that you should be using fprintf.
Paul
Paul on 3 Mar 2023
Edited: Paul on 3 Mar 2023
This image is from the assignment. Yeah, it seems weird to me too. But I also may not be understanding what it means fully.

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