Find the exact multiple of a number by zero padding values.

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A = 13848 x 1
and I want to reshape into a 173(matters a lot) by 80 or 81(this doesn't matter) but that isn't possible as 13848 isn't divible by 173.
So I want a way where it reads A and calculates the next perfect value which is 14013 by zero padding A.
I could just remove 8 from A but I don't loose data but I don't mind zero padding to A towards the end.
  1 Comment
CalebJones
CalebJones on 5 Feb 2020
Edited: CalebJones on 5 Feb 2020
I could just manually zero pad A, but I want it to be as automated as possible.

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Accepted Answer

Stephen23
Stephen23 on 5 Feb 2020
Edited: Stephen23 on 5 Feb 2020
Method One: create the output matrix first, then use indexing to add the values:
R = 173;
B = zeros(R,ceil(numel(A)/R));
B(1:numel(A)) = A(:);
Method Two: pad some extra zeros and then remove the superfluous elements:
R = 173;
X = 1:R*fix((1+numel(A))/R)
B = [A;zeros(R,1)];
B = reshape(B(X),R,[]);
  4 Comments
Stephen23
Stephen23 on 5 Feb 2020
Edited: Stephen23 on 5 Feb 2020
Why did you convert this index into a table?:
X = array2table(1:R*fix((1+A)/R))
X is supposed to be a numeric index vector (just like in my answer). Converting it into a table is unlikely to work, and just makes the code pointlessly complex.
Apparently your data are in a table, something that you omitted to mention in your question. I doubt that you have really considered what it means to reshape a table: a table is a container class which contains multiple different variables, it is not a simple array class that can be reshaped, as the variables are not one contiguous array stored in memory. In any case, to reshape you should probably get the appropriate array out of the table first:
CalebJones
CalebJones on 5 Feb 2020
A = size(right_pc,1);
R = 173;
X = 1:R*fix(1+A/R);
B = [right_pc.HbO ; zeros(R,1)];
B = reshape(B(X),R,[]);
Ah yes, SWEEET!
Fixed !
Thanks bud.

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More Answers (1)

KSSV
KSSV on 5 Feb 2020
Edited: KSSV on 5 Feb 2020
A = rand(13848,1) ;
n = length(A) ; % length of A
r = 80 ; % to reshape by this dimension
N = mod(-mod(n,r),r); % get the number of zeros to be appended
A = [A ; zeros(N,1)] ; % append zeros
iwant = reshape(A,r,[]) ; % reshape
  2 Comments
Stephen23
Stephen23 on 5 Feb 2020
CalebJones's "Answer" moved here:
getting an error.
n = size(right_pc,1) ; % length of A
r = 80; % to reshape by this dimension
N = mod(-mod(n,r),r); % get the number of zeros to be appended
A = [right_pc(:,1) ; zeros(N,1)] ; % append zeros
iwant = reshape(A,r,[]) ; % reshape
when i tried to run...this
N = mod(-mod(n,r),r);
Index in position 1 exceeds array bounds (must not exceed 173).
I have atteched a mat file as well.
Stephen23
Stephen23 on 5 Feb 2020
You have created a variable named mod. Clear that variable from the workspace.

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