A = [1 10 16 23];
A-3:A+2 will result in [-2,-1,0,1,2,3]; In other words colon operates only on the first element of array A. However I want to apply A-3:A+2 on all the elements of A; I know I can get this by a loop, like :
u=;for i=1:4, u=[u,A(i)-3:A(i)+2]; end
However I wonder if there is a way to do this without using loop. (The actual array I am working with is too long to loop through it.)
This sounds like a super simple question but I have no ides how to do it in a simple way (other than looping).
I so much appreciate any help.