Asked by Ede gerlderlands
on 17 Nov 2012

I have an equation of the form

a(x) + x.da/dx = 2x , x= 1:1:12

f(x) is known and has different values for different x. My question is how can I find values of 'a' in matlab through iteration. Am new to matlab and any help is highly appreciated.

Answer by Azzi Abdelmalek
on 17 Nov 2012

Edited by Azzi Abdelmalek
on 17 Nov 2012

Accepted Answer

save this function with the name **dif_eq**

function da=dif_eq(x,a,tim,f) f1=interp1(tim,f,x) da=(f1-a)/x;

then call the function:

t=[0.1:10]; % time vector x0=0; % initial condition f=rand(1,numel(t)); % your vector f, same length as vector time t [X,A]=ode45(@(x,a) dif_eq(x,a,t,f),t,x0); plot(X,A)

Ede gerlderlands
on 17 Nov 2012

Many many thanks ...don't have words for your help....this was so troublesome...

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Answer by Azzi Abdelmalek
on 17 Nov 2012

Edited by Azzi Abdelmalek
on 17 Nov 2012

save this funnction with the name **dif_eq**

function da=dif_eq(x,a) f=sin(x); for example da=(f-a)/x;

then type in Matlab command

[x,res]=ode45(@dif_eq,[1 12],0)

Ede gerlderlands
on 17 Nov 2012

Yes, I did that my actual 'f' is not function actually it is collection of different values. such as 0.4 0.25 0.6.....

Ede gerlderlands
on 17 Nov 2012

Thanks Azziz , I understand your function but 'a' itself isn't known and that's my problem.

Azzi Abdelmalek
on 17 Nov 2012

Ede, the problem is not a, we are looking for a. I can't use f with different values in the equation. If I find something I will post it, or someone else will do.

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