How can I increase the vertical size of subplots?

Hi,

I'm trying to increase the verticle size of my subplots, but I'm having no luck. Can someone please let me know where I've gone wrong.

My code is:

suplotTitle = {'0.4mA', '0.6mA', '0.8mA', '1.2mA', '1.6mA'}; 
f1=figure('position', [10, 10, 800, 1000]);

for ii=1:5
    subplot(6,2,2*ii-1);
    b1 = bar(conRR(2:end,1), conRR(2:end,ii+1));
    b1.FaceColor = '#D95319';
    b1.EdgeColor = 'none';
    xticks(1:1:16);
    ylim([0 80]);
    title(suplotTitle{ii})
    set(gca, 'FontSize', 10);
    box off
    
    if ii < 5
        set(gca,'XTick', []);
    end
end

subplot(6,2,5), ylabel('Respiratory Rate (BPM)')
subplot(6,2,9), xlabel('Number of rats (N)')


for ii=1:5
    s2 = subplot(6,2,2*ii);
    b2 = bar(b9RR(2:end,1), b9RR(2:end,ii+1));
    b2.FaceColor = '#0072BD';
    b2.EdgeColor = 'none';
    xticks(1:1:16);
    ylim([0 80]);
    title(suplotTitle{ii})
    
    box off
    set(gca, 'FontSize', 10);
    if ii < 5

        set(gca,'XTick', []);
    end 
    
end

subplot(6,2,6), ylabel('Respiratory Rate (BPM)');
subplot(6,2,10), xlabel('Number of rats (N)');

%Add legend
hL = subplot(6,2,[11,12]);
poshL = get(hL,'position');    

lgd = legend(hL,[b1,b2],'Control','Intervention');
legend box off;
set(lgd,'position',poshL,'Orientation','horizontal', 'FontSize', 12);
axis(hL,'off');                 % Turning its axis off

%Add main title
t = sgtitle('Respiratory Rate');
t.FontSize = 15;
t.FontWeight = 'bold';

At the moment my Figure looks like this:

Thanks in advance.

[Paresh yeole]

Try using :

set(gca,'Units','centimeters','Position', [0 0 7.5 6])

for each subplot.

[NA]

thank you

Answer 1

[Star Strider]

I got this to work with the previous code, however I couldn’t get it to work with the code you posted. You will need to make the appropriate adjustments to do that.

The change is to add these two lines in each looop:

    PosVec = Ax.Position;
    Ax.Position = PosVec+[0 -0.005 0 0.005]; 

and after both loops:

f1.Position = f1.Position+[0 -300 0 300];

That should get you started.

The (Revised) Code —

conRR = [(0:10).' rand(11,5)*80];                               % Create Matrix
b9RR = [(0:10).' rand(11,5)*80];                                % Create Matrix

suplotTitle = {'0.4mA', '0.6mA', '0.8mA', '1.2mA', '1.6mA'}; 
f1=figure
for ii=1:5
    Ax = subplot(5,2,2*ii-1);
    b1 = bar(conRR(2:end,1), conRR(2:end,ii+1));
    b1.FaceColor = '#D95319';
    b1.EdgeColor = 'none';
    xticks(1:1:16);
    ylim([0 80]);
    title(suplotTitle{ii})
    PosVec = Ax.Position;
    Ax.Position = PosVec+[0 -0.005 0 0.005];
end

for ii=1:5
    Ax = subplot(5,2,2*ii);
    b2 = bar(b9RR(2:end,1), b9RR(2:end,ii+1));
    b2.FaceColor = '#0072BD';
    b2.EdgeColor = 'none';
    xticks(1:1:16);
    ylim([0 80]);
    title(suplotTitle{ii})
    PosVec = Ax.Position;
    Ax.Position = PosVec+[0 -0.005 0 0.005];
end

f1.Position = f1.Position+[0 -300 0 300];

The Plots —

Original:

This code:

[NA]

Thanks Star Strider. The subplots look great, but I couldn't figure out how to add the x-y-labels and the legend with my current code. I'd always get an error for some reason. But nevertheless, I found a way around it - I just created a legend with the data from my subplots and then manually positioned them. This seemed to work relatively well - good enough to present the data at tomorrow's meeting anyway! Thanks again!

[Star Strider]

As always, my pleasure!

Answer 2

[Bjorn Gustavsson]

You can manually adjust the subplot's axes position like this:

sph = subplot(3,2,1);
dx0 = 0;
dy0 = -0.05;
dwithx = 0.0;
dwithy = 0.1;
set(sph,'position',get(sph,'position')+[dx0,dy0,dwithx,dwithy])

You will have to modify this heavily, but the tweaking shouldn't be too bad for one figure - and might be "impossible" to get right for an absolutely general sub-plots configuration.

There are a number of file-exchange contributions that handles this, or different parts of this:

gettightsubplothandles, tight_subplot, panel, tight-subplot-with-units-in-centimeter, border-less-tight-subplot.

Hopfully you find something useful.

HTH

[NA]

Thanks