Finding the solution of a system of equations

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Steewz
Steewz on 18 Jun 2020
Commented: Kshitij Chhabra on 22 Jun 2020
Hey i would like to find the solutions for this system assuming that my unknows are X Y and Z
solve doesnt work
syms X Y Z
eq1=sqrt((a1-X)^2+(b1-Y)^2+(c1-Z)^2) == D1+R1;
eq2=sqrt((a2-X)^2+(b2-Y)^2+(c2-Z)^2) == D2+R2;
eq3=sqrt((a3-X)^2+(b3-Y)^2+(c3-Z)^2) == D3+R3;
eq4=sqrt((a4-X)^2+(b4-Y)^2+(c4-Z)^2) == D4+R4;
TY

Answers (1)

Kshitij Chhabra
Kshitij Chhabra on 18 Jun 2020
Hi Steewz,
From the question, I understand that you want to solve the given set of quadratic equations for X,Y,Z. Since not specified in the question, I am assuming the other variables as constants which can be specified later(or you can assign them to be syms variable too).
For the above problem you may try using solve function in the following way:
sol = solve([eq1, eq2, eq3], [X, Y, Z]);
For accessing the results you may use:
sol.X;
sol.Y;
sol.Z;
  2 Comments
Kshitij Chhabra
Kshitij Chhabra on 22 Jun 2020
Hi,
Writing the above code as:
sol = solve([eq1, eq2, eq3,eq4], [X, Y, Z]);
should solve the problem too, If it's giving some unexpected behavior it'd be helpful if you could share the values of constant as well.

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