Subscripted assignment dimension mismatch.

1 view (last 30 days)
Hello, I am attempting to separate a large matrix into two parts for kernel formation for clustering with a kernel k-means algorithm. While I would ordinarily jus reshape it into a third dimension, this option is impossible given that the number of columns in the matrix in question is odd (24021). I have been unable to perform any of the things that I have seen before, such as indexing. Below is the method I tried, which returned the above error message.
EDU>> for n=1:24041
if n<=12021
split{1}(n)=test(:,n);
elseif n>12021
split{2}(n-12021)=test(:,n)
end
end
Subscripted assignment dimension mismatch.
If anyone can tell me what is going on, I would greatly appreciate it. Thanks in advance.

Accepted Answer

Walter Roberson
Walter Roberson on 12 Jan 2013
split{1} = test(:,1:12021);
split{2} = test(:,12022:end);
  1 Comment
Jacob Moses
Jacob Moses on 12 Jan 2013
This worked perfectly, and was easiest for me to understand. Thank you so much!

Sign in to comment.

More Answers (1)

José-Luis
José-Luis on 12 Jan 2013
Edited: José-Luis on 12 Jan 2013
You are probably trying to assign a matrix to a scalar:
split{1}(n)=test(:,n);
split{1}(n) is most likely a scalar
test(:,n) is probably a column vector
  3 Comments
José-Luis
José-Luis on 12 Jan 2013
No, it is a column vector as far as I understand it.
José-Luis
José-Luis on 12 Jan 2013
Now I see what you meant. I need some coffee.

Sign in to comment.

Products

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!