Answer by PG
on 25 Jan 2013

Edited by Jan Simon
on 25 Jan 2013

out = rand(1, 1); decimal_out = floor(out * 100000000); decimal_out = decimal_out\100000000;

Cy
on 26 Oct 2015

Don't you mean "decimal_out/100000000"?

Thorsten
on 26 Oct 2015

Your're right, that's a typo, must read /. Of course you can do it more efficiently in one line (for example, to generate a row vector of four random values):

x = floor(rand(1,4)*1e10)/1e10;

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Answer by Jan Simon
on 25 Jan 2013

What about using `rand()` directly, because it satisfies: at least 8 decimal digits already?

Jan Simon
on 25 Jan 2013

The limitation to 4 digits appears in the command line only, see: help format.

format long g

disp(rand(2,2))

Although I assume your code is just an abbreviated example, I recommend **not** to use "min" and "max" as names of variables, because this shadows frequently used Matlab commands.

However, I still do not understand your question. What does "fixing the number of decimal points" mean? RAND does reply values like 0.00000000001 also, so what is the problem.

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Answer by Evgeny Pr
on 25 Jan 2013

Edited by Evgeny Pr
on 25 Jan 2013

Do you have the distribution law for pseudo-random numbers for your problem? You can use RAND function for generate uniformly distributed numbers and define its non-linear (or linear) transformation function:

numbers = rand(10); transformedNumbers = transform_function(numbers);

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## 1 Comment

## Jan Simon (view profile)

Direct link to this comment:https://www.mathworks.com/matlabcentral/answers/59849-decimal-random-number-generator#comment_125490

Where did all the comments go? Did you delete them? If so, why? Without them our answers looks a little bit unmotivated, not to say lunatic. Therefore removing important data from a thread is not wanted.

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