plotting libnez taylor series

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hi there i have tried to plot libnez's taylor series as a line graph but it will not show up. correctly it only plots the same reslut value for all terms given. I want to plot 20 terms but am have difficultly doing so. Can anyone help me out?
the function is : pi= 4- 4/3+ 4/5- 4/7....
This is what I have so far thanks to Youssef KHMOU ...
value= input('how many values would you like:');
result=zeros(20,1);
signchange= 1;
result(1)=4;
for k= 1:value
term = signchange * 4/(2*k-1);
result(k+1) =result(k)+ term;
signchange = signchange * (-1) ;
end
plot(result)
the only problem is that I want it to plot somehow from terms 0:20
  2 Comments
AngelsaAtWar
AngelsaAtWar on 11 Feb 2013
the series is 4-4/3+4/5-4/7.....
Youssef  Khmou
Youssef Khmou on 11 Feb 2013
write the index form of the series : per example :
N
-
\ n*(n+1)
/ --------
- (n+3)* n
n=0

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Accepted Answer

Youssef  Khmou
Youssef Khmou on 11 Feb 2013
esult=0.0 ;
signchange= 1;
for k = 1:1:value
term = signchange * 4/(2*k-1);
result = (result + term)
signchange = signchange * -1 ;
x=1:1: value;
y=result;
plot(x,y,'ok'); hold on end
hold off
  2 Comments
Youssef  Khmou
Youssef Khmou on 11 Feb 2013
yes, but you have to specify your question, Taylor LEIBNIZ series is general form, you want apply the formula on what function : per example :
sin(x) = Sum (n=0, infinity) (-1)^n * (x^2n+1) / (2n+1)!
, take a look at the answer below .

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More Answers (1)

Youssef  Khmou
Youssef Khmou on 11 Feb 2013
Edited: Youssef Khmou on 11 Feb 2013
AngelsaAtWar :
You have to re-post the question with the function you want use and give a general index forumla :
here is you code with 400 iterations :
value=400;
result=zeros(40,1);
signchange= 1;
result(1)=4;
for k = 1:value-1
term = signchange * 4/(2*k-1);
result(k+1) =result(k)+ term;
signchange = signchange * (-1) ;
end
plot(result)
  2 Comments
AngelsaAtWar
AngelsaAtWar on 12 Feb 2013
I edited my question above like you asked me to
Youssef  Khmou
Youssef Khmou on 12 Feb 2013
Edited: Youssef Khmou on 12 Feb 2013
ok,
what about the last code, is that what you want ( damped sinusoidal function like) ?
if you only want to plot 20, then give 20 as input to value . Or can you give 100000 , but plot only 20 or truncate other elements starting from 21 to end , you have may options,
plot(result(1:20)) % if you gave more than 20 to values or :
result(21:end)=[], plot(result)

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