I tried to use the msgbox function in matlab, which I found here:
I tried to take the formula to display at which i we are currrently with the code:
h = msgbox(i)
unfortunately it's not working at all. From VBA I know that it's just necessary to enter msgbox and the variable, but that doesn't work either
what do I need t change?
You need to pass it a string
for k = 1 : 10 message = sprintf('k = %4d\n', k); uiwait(msgbox(message)); % You can use fprintf() instead if you don't want to prompt the user. fprintf(message); % Goes to command window. end
Or better yet, use questdlg() so the user can have an opportunity to break out of your 1000 iteration loop:
for k = 1 : 10 message = sprintf('k = %4d\nContinue?', k); reply = questdlg(message, 'Continue', 'OK', 'Cancel', 'OK'); if strcmpi(reply, 'Cancel') % User said Cancel, so exit. break; end end
I used k as a loop variable because you're not supposed to use i or j - they're the imaginary variable.
>> h = msgbox('This is my message') h = 0.0012 >>
works fine here. Message should be a string.
[Added:] To show the value of the numeric variable: i
h = msgbox( num2str( i ) )
VB do things more automagically than Matlab. Here you need to do the conversion explicitely.