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Problem with cross correlation

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Ivan Mich
Ivan Mich on 2 Feb 2021
Edited: Ivan Mich on 24 Feb 2021
Hello. I have a problem with a code. I have two kinds of data (lets call them a and b). These are cells, and in each cell I have double/numbers (see images attached). i would like to cross correlate , using a loop, data of a with data of b. I am using the following code:
but I realise that the results are wrong, as I should have 100% correlation bacause of the similarity of the numbers.
for i=1:numel(a)
[c,lag]=crosscorr(a{i},b{i})
r = [0.65, 1];
ii = c >= r(1) & c <= r(2)
% this finds the index of he rows(2) that have x in between
idx = find(abs(c) > r(1) & abs(c) <= r(2));
% number of intervals with positive check
numIdx{i} = sum(abs(c) > r(1) & abs(c) <= r(2))
Final{i}=(numIdx{i})'
n=Final'
end
Could you help me in order to fix it?

Answers (1)

KALYAN ACHARJYA
KALYAN ACHARJYA on 2 Feb 2021
Edited: KALYAN ACHARJYA on 2 Feb 2021
Might be you are looking for corrcoef Correlation coefficients.
or
r = xcorr(x,y) returns the cross-correlation of two discrete-time sequences. Cross-correlation measures the similarity between a vector x and shifted (lagged) copies of a vector y as a function of the lag.
In cross correlation,refer the MATLAB docs Specify Additional Lags for Cross-Correlation
Please refer the following external link to see, how to compute the cross corelation between discrete data
x [n] = {-3, 2, -1, 1}
y [n] = {-1, 0, -3, 2}
It's better to refer any standard signal analysis text book to undestand various types for corelation between two discrete signal data.
Example:
a=cell2mat({2,1,17,5,19});
b=cell2mat({2,1,17,5,19});
Results:
>> xcorr2(a,b)
ans =
38 29 362 199 680 199 362 29 38
>> xcorr(a); %Same as xcorr2 if both a and b are same
ans =
38.0000 29.0000 362.0000 199.0000 680.0000 199.0000 362.0000 29.0000 38.0000
>> result=crosscorr(a,b);
result =
-0.2369 -0.1835 0.1964 -0.2761 1.0000 -0.2761 0.1964 -0.1835 -0.2369
>> corrcoef(a,b)
ans =
1.0000 1.0000
1.0000 1.0000
  2 Comments
Ivan Mich
Ivan Mich on 2 Feb 2021
Could you please help me?
Thank you in advance

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