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Contour and Scatter in the same figure

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Hello all,
I have a problem using the functions "contour" and "scatter3". I hope I can explain it clearly: I have 2 triplets of data: x,y,w and x,y,z. The x and y coordinates are the same for both of them.
I know how to represent a triplet using the function "scatter3". I also know how to make a contour plot of these data (separetely for the w and z coordinates) using the meshgrid and griddata functions.
The problem I have happens when I want to make a contour plot (with the values of w) and a scatter3 plot(with the z values) in the same figure. Actually, I can represent both plots simultaneously. The contour plot is normal, but the scatter3 plot has all the points with the same color, and I wanted it to have different colour depending on the values of its z variable (as usual). This way I could see easier (with the help of the different colours) the values of both variables in one single plot.
Does anyone know how to do it??
Thanks in advance!
P.S. I have tried this in Matlab 7.3 and 7.6 and it does not work in any of them.
  1 Comment
Walter Roberson
Walter Roberson on 14 May 2011
Please show the appropriate section of your code.

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Accepted Answer

Walter Roberson
Walter Roberson on 16 May 2011
contour internally uses integer CData values if colors are not specified, and normally the integers get scaled to the total range of the color map.
If scatter3 is specifically used with the raw zdata values as the colors, then when used in isolation, the raw zdata value range would get scaled to the total range of the color map.
Put these two together and unless the zdata value range happens to be from 1 to the number of contours, the color transform of one or the other is going to be messed up.
I can think of a couple of ways that one might compensate for this, but before going in to them, I would rather that xkudsraw indicate how their code is currently constructed... no point in my detailing a solution if I have guessed wrong about the problem ;-)
Patrick Kalita
Patrick Kalita on 16 May 2011
Thanks for the additional info. I had actually thought about address that case in my original answer, but I thought I'd keep it simple. Anyway, I've updated my answer.

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More Answers (2)

Patrick Kalita
Patrick Kalita on 16 May 2011
Are you using the optional fifth input argument of scatter3? That is the input that controls the color of the points.
Here's an example:
% Make up some data
x = rand(1,100);
y = rand(1,100);
z = x.^2 + y.^2;
w = x + y;
% Make a contour plot with the w-data.
[xg, yg] = meshgrid(0 : 0.1 : 1);
wg = griddata(x,y,w,xg,yg);
% Make a scatter3 plot with the z-data, and also use the z-data to color the markers. The fourth input is empty ( [] ) because we want the markers to all be the same size.
hold on
scatter3(x, y, z, [], z);
% Just for good measure
A word of caution: you may get surprising (although correct) results if w and z have vastly different ranges. When w and z have different ranges, the axes will expand its CLim property to encompass the entire range of w and z. For example, if w goes from [0 1] and z goes from [500 501], when both plots are added to the same figure, the axes' CLim will be set to [0 501]. That means the contour lines will pick colors from very very bottom of the colormap, and the scatter markers will pick up colors from the very very top of the colormap.
There are a few things you could do to change this behavior. The simplest thing is that you could scale w and/or z so that they occupy the same range.
Or you could use the axes Colormap property and a function like ind2rgb, and pass RGB colors to scatter3. That's a bit of an advanced maneuver, but then the colors of the scatter3 point markers don't rely on the axes CLim property. Here's a very simplified example to illustrate:
hold on
scatter3(1:5:25, 1:5:25, 1:5:25, [], [0 0 0; 1 0 0; 0 1 0; 0 0 1; 1 1 0], 'filled')
In reality, you wouldn't manually specify the colors like that -- you would generate that from the colormap and ind2rgb.
Walter Roberson
Walter Roberson on 9 Feb 2020
With new enough matlab see rescale(). If your version is not new enough for that then see the poorly named mat2gray

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xkudsraw on 18 May 2011
Problem solved :)I have used the function ind2rgb to obtain the new colormap for the z data. Thanks a lot you both!!

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