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How to solve problem with function lscuvfit, whena i have ther integral without xmax? Thank you.

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Lenny Guitar
Lenny Guitar on 10 Apr 2021
Commented: Lenny Guitar on 11 Apr 2021
How to solve this proble please?
y= [0.871 0.928 0.946 0.952 0.958 0.965 0.971 0.979 0.987 0.992 0.995 0.997];
x=[0.2 0.5 0.7 0.8 0.9 1.1 1.5 2.3 4.6 9.2 22.9 45.9];
x0=[5 0.03];
fun=@(par,y)integral(((2-par(1))./(1-par(1)))^(5/2),0,y);
sol= lsqcurvefit(fun,x0,x,y);
The right solution of par (1) and y must be a 0.965.

Answers (1)

Matt J
Matt J on 10 Apr 2021
Edited: Matt J on 10 Apr 2021
The right solution of par (1) and y must be a 0.965.
Why do you speak of y as if it is an unknown? The unknown parameters are supposed to be the vector elements par(i). Also. your model fun(par,y) doesn't look right for several reasons,
  • The integrand passed to integral() is not a function handle
  • You have 2 unknowns in x0, but only 1 unknown in par
  • You've written it in terms of par and y instead of par and x
Also note that if the integrand is intended to be a par-dependent constant, you can do the integral analytically. You don't need the integral() coommand.
  1 Comment
Lenny Guitar
Lenny Guitar on 11 Apr 2021
Thank you for you answer.I try to correct this expression, but still without working this. I spent lot of time on this problem, but i dont know, how solve this. Thank you again for your help.

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