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Remove text in a string with numbers

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How can I remove the text part and obtain a vector of just the last numbers?
e.g
Model1__DK1_5450.0
Model2__DK2_6969.0
Model3__DK3_3398.0

Accepted Answer

Image Analyst
Image Analyst on 20 Apr 2021
Edited: Image Analyst on 20 Apr 2021
You need to use digitsPattern:
txt = 'Model1__DK1_5450.0 '
pat = digitsPattern;
onlyNumbers = extract(txt, pat)
onlyNumbers =
4×1 cell array
{'1' }
{'1' }
{'5450'}
{'0' }
or you can use logical indexing:
digitIndexes = txt >= '0' & txt <= '9';
onlyNumbers = txt(digitIndexes)
onlyNumbers =
'1154500'
Or you can do fancier parsing if you just want certain numbers. Such as:
setOf4Digits = onlyNumbers(3:end-1); % Get only the 5450
Do you want the underlines, dots, and minus signs included?
  3 Comments
Image Analyst
Image Analyst on 20 Apr 2021
Well, you can either use indexing like this:
txt = 'Model1__DK1_5450.0 '
lastUnderlineIndex = find(txt == '_', 1, 'last');
% Extract from one past the last underline onwards.
onlyNumbers = strtrim(txt(lastUnderlineIndex + 1: end)) % strtrim gets rid of trailing space.
or you can use the regexp() method like Star shows. Your choice - either works.
In your original post, you posted strings with a trailing space. If you don't have that, you can omit the call to strtrim().
Image Analyst
Image Analyst on 21 Apr 2021
@Chiara Scarpellini, just checking back. You did not accept either answer. Are you still there?

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