Rearranging array based on number of steps.
1 view (last 30 days)
Show older comments
Santos García Rosado
on 1 Jun 2021
Commented: Santos García Rosado
on 1 Jun 2021
Hi everybody,
Let's say I have a vector such as:
A = (1:24)
And I'd like to separate this array into a 2x12 matrix where the first row will show the first 3 positions skipping the next three and so on... The second row will do the same thing but starting from the fourth position. This is the expexted output:
Output = [1 2 3 7 8 9 13 14 15 19 20 21; 4 5 6 10 11 12 16 17 18 22 23 24]
I could do this manually, but some times I'd like it to take 2 or 4 steps instead of 3, as it is in the example above.
Any ideas of how to to achieve this?
Thank you in advanced,
Santos
0 Comments
Accepted Answer
More Answers (0)
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!