How to find result in the same metric ??

It wasn’t what I thought it would be. The final result in the variable "fr" has the same value or incorrect . what should i do?

x = rand(100, 2);
col1 = x.data(:,1); 
col2 = x.data(:,2);  
n = 2;
val = zeros(n,1);
fr = zeros(n,2);
for i=1:n
[val(i) , idA] = min(col2); 
col2(idA) = []; % remove the first value
end
fr=col1(idA);

I would like row and colum result of variable fr is like variable val?

Answer 1

[Walter Roberson]

[val(i) , idA] = min(col2); 

You are taking min() of the same thing each time, so you get the same result each time.

[yanisa ketsuwan]

yes, This problem could be solved by col2(idA) = [].

But I get the same answer when browsing. Row and column in variable col1. What should I do?

[Walter Roberson]

Consider using mink to find the indices of the n minimum entries of the first column and use the indices to index the rows