i want to knw the working of this code section:

for i=1:(row-25)
  for j=1:24
      rv(i)=rv(i)+rv(i+1);
  end;
  rv(i)=rv(i)/25;
end;

where row means number of row in binary image.and rv means row variance of that image.

Answer 1

[Image Analyst]

They're getting the averaged row variance (rv) over a pair of lines. So they're taking the row variance and adding the rv from the next row. Then they divide by 25 to scale it (for some reason, instead of 2 which would get you the average). Just follow the logic:

rv(1) = rv(1)+rv(2);
rv(2) = rv(2)+rv(3);
rv(3) = rv(3)+rv(4);
etc.

The loop over j is totally useless - it just calculates the same rv(i) 24 times. There is no need at all for the j loop!

It doesn't make much sense to me why you'd want to do that.

[Vandana]

Thank u very much sir Sir can I use 2 instead of 25?

[Image Analyst]

Well, yes - but that assumes that all the indexes inside your inner loop are i. I have my doubts. I mean, why have a loop over j if you never refer to j??? If I were you, I'd check what I wrote and make sure all your i's are really i's and none of them is supposed to be a j. Because it just doesn't make sense that someone would have a loop over j for no reason.