How can I create this matrix?

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  1 Comment
KSSV
KSSV on 4 Aug 2021
An example will hep us to help you.

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Accepted Answer

Stephen23
Stephen23 on 4 Aug 2021
n = 5;
r = 2:5;
F = @(k)any(permute(nchoosek(1:n,k),[3,1,2])==(1:n).',3);
M = cell2mat(arrayfun(F,r,'uni',0))
M = 5×26 logical array
1 1 1 1 0 0 0 0 0 0 1 1 1 1 1 1 0 0 0 0 1 1 1 1 0 1 1 0 0 0 1 1 1 0 0 0 1 1 1 0 0 0 1 1 1 0 1 1 1 0 1 1 0 1 0 0 1 0 0 1 1 0 1 0 0 1 1 0 1 1 0 1 1 1 0 1 1 1 0 0 1 0 0 1 0 1 0 1 0 1 0 1 0 1 1 0 1 1 1 0 1 1 1 1 0 0 0 1 0 0 1 0 1 1 0 0 1 0 1 1 0 1 1 1 0 1 1 1 1 1
  4 Comments
Walter Roberson
Walter Roberson on 19 Aug 2021
You might be able to fit the 50 case. Change to
F = @(k)any(permute(nchoosek(uint8(1:n),k),[3,1,2])==uint8(1:n).',3);

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