Asked by Jenn
on 9 Oct 2013

Can someone please help me with this, I am new using the program and I really do not know what to do,

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Answer by sixwwwwww
on 10 Oct 2013

Edited by sixwwwwww
on 10 Oct 2013

I will come back to it soon

sixwwwwww
on 10 Oct 2013

But for different initial conditions we will have different integration constants values. Then it should work

Walter Roberson
on 10 Oct 2013

Even with specific boundary conditions, the integrals along the way have the singularity at x = 0 or y = 0

sixwwwwww
on 10 Oct 2013

Probably you are right it's not easy to solve it directly. Thanks for correction

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Answer by Walter Roberson
on 10 Oct 2013

Hint: for

x' = 2*x^3 + sin(x) %random example

you would code

fun = @(x) 2 * x.^3 + sin(x); ode45(fun, [StartTime, EndTime], [InitialX, InitialY])

such as

ode45(fun, [0 20], [3 7])

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## 1 Comment

## Walter Roberson (view profile)

Direct link to this comment:https://www.mathworks.com/matlabcentral/answers/89740-solve-the-system-x-4x-2xy-y-3y-3xy-with-initial-condition-varying-in-the-rectangle-0-7-x#comment_173337

Nasty little system, not very tractable to analysis.

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