MATLAB Answers


How do I preallocate memory for a structure in MATLAB 7.6 (R2008a)?

Asked by MathWorks Support Team on 23 Sep 2013
Latest activity Commented on by Walter Roberson
on 15 Feb 2017 at 5:02

I would like to know how to preallocate memory for a structure.

1 Answer

Answer by MathWorks Support Team on 23 Sep 2013
 Accepted answer

There is a way to preallocate memory for a structure in MATLAB 7.6 (R2008a) using the STRUCT and REPMAT commands.

EXAMPLE 1: A structure with two fields



field_names = {'field1','field2'}; % Cell with field names
empty_cells = repmat(cell(1),1,numel(field_names));
entries = {field_names{:} ; empty_cells{:}};
s = struct(entries{:}); 

EXAMPLE 2: A structure with a field with a subfield


s = struct('field1',struct('subfield',cell(1))); 

EXAMPLE 3: An array of structures




s = struct('field1',cell(1));
v = repmat(s,100,1);

Even though the data elements pointed to by the different fields in a structure are not stored contiguously, a benefit of preallocating structures is that you avoid the (possibly time-consuming) operation of dynamically growing the structure field header. Please refer to the following documentation page for more information:


for command

empty_cells = repmat(cell(1),1,numel(field_names));

can't we use [], for defining empty cells under field_name, like

filed_name = {'field1',[],'field2',[]};  

The line

empty_cells = repmat(cell(1),1,numel(field_names));

creates a cell array of copies of [] . The line

entries = {field_names{:} ; empty_cells{:}};

arranges those copies below the field names, like

{ 'first', 'second', 'third';
  [],      [],       []      }

and the line

s = struct(entries{:}); 

converts that to

a = struct('first', [], 'second', [], 'third', [])

so already [] is being used.

The code given in the first part of the solution is code to automatically generate this just given the field names.

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