Cody

# Problem 1102. USC Fall 2012 ACM : Find Largest Water Concentration

Solution 174926

Submitted on 8 Dec 2012 by Richard Zapor
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### Test Suite

Test Status Code Input and Output
1   Pass
%% %http://contest.usc.edu/index.php/Fall12/Home?action=download&upname=water.in.txt tic urlwrite('http://contest.usc.edu/index.php/Fall12/Home?action=download&upname=water.in.txt','water_in.txt'); toc

```Elapsed time is 0.529378 seconds. ```

2   Pass
%% fid=fopen('water_in.txt','r'); w_area_expect=[8 16;100 100;0 1;1 1;5 9;186 675;23 110; 480 2500;102 2500;61 400; ... 73 930;160 441; 678 800; 55 361; 53 195;216 1296;199 1110;81 576;232 552;12 30;9 25;15 25;25 143; ... 66 120;2500 2500;270 1680;264 900;292 1365;748 2401;244 609;315 1296;214 1188]; qty=fscanf(fid,'%i',1); for q=1:qty n = fscanf(fid,'%i %i %i\n',3)'; % rows / cols / min rect s=n(3); n=n(1:2); strv=fgetl(fid); iswater=strv; A=zeros(n); % Format is rows, columns for i=1:n(1) strv = fgetl(fid); A(i,:) = strv; end A=char(A); [w,w_area]=Water_analysis(A,iswater,s); assert(isequal([w w_area],w_area_expect(q,:))); end fprintf('Processing Complete\n\n') fclose(fid); toc

``` M = 6 N = 13 M = 10 N = 10 M = 1 N = 1 M = 1 N = 1 M = 5 N = 3 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 M = 50 N = 50 Processing Complete Elapsed time is 8.120402 seconds. ```