Problem 37. Pascal's Triangle

Solution 181535

Submitted on 25 Dec 2012 by Youssef Khmou

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Youssef Khmou on 25 Dec 2012

We used a subfunction Cpn(n,p)
Y=factorial(p)/(factorial(n)*factorial(p-n)) instead of the function "nchoosek" .

Test	Status	Code Input and Output
1	Pass	%% n = 0; correct = [1]; assert(isequal(pascalTri(n),correct))
2	Pass	%% n = 1; correct = [1 1]; assert(isequal(pascalTri(n),correct))
3	Pass	%% n = 2; correct = [1 2 1]; assert(isequal(pascalTri(n),correct))
4	Pass	%% n = 3; correct = [1 3 3 1]; assert(isequal(pascalTri(n),correct))
5	Pass	%% n = 10; correct = [1 10 45 120 210 252 210 120 45 10 1]; assert(isequal(pascalTri(n),correct))