Cody

# Problem 413. Back to basics 23 - Triangular matrix

Solution 228194

Submitted on 8 Apr 2013 by VIVI
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``` lx = 4 x = 1 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 x = 1 1 1 1 1 1 1 0 1 1 1 0 1 1 1 1 x = 1 1 1 0 1 1 1 0 1 1 1 0 1 1 1 1 x = 1 1 1 0 1 1 0 0 1 1 1 0 1 1 1 1 x = 1 1 0 0 1 1 0 0 1 1 1 0 1 1 1 1 x = 1 0 0 0 1 1 0 0 1 1 1 0 1 1 1 1 y = 1 0 0 0 1 1 0 0 1 1 1 0 1 1 1 1 ```
``` lx = 5 x = 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 x = 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 0 1 1 1 1 1 x = 1 1 1 1 1 1 1 1 1 0 1 1 1 1 0 1 1 1 1 0 1 1 1 1 1 x = 1 1 1 1 0 1 1 1 1 0 1 1 1 1 0 1 1 1 1 0 1 1 1 1 1 x = 1 1 1 1 0 1 1 1 1 0 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 x = 1 1 1 1 0 1 1 1 0 0 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 x = 1 1 1 0 0 1 1 1 0 0 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 x = 1 1 1 0 0 1 1 0 0 0 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 x = 1 1 0 0 0 1 1 0 0 0 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 x = 1 0 0 0 0 1 1 0 0 0 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 y = 1 0 0 0 0 1 1 0 0 0 1 1 1 0 0 1 1 1 1 0 1 1 1 1 1 ```