Cody

# Problem 43118. Reduce the logic

Solution 1000094

Submitted on 7 Oct 2016 by George Papazafeiropoulos
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### Test Suite

Test Status Code Input and Output
1   Pass
x = true; y = false; z = true; y_correct = ((x&y)|z)&((z|x&y)|(z&y|x))|((x&z)|z)&((y|x&z)|(z&x|y))|(x|y|z); assert(isequal(your_fcn_name(x,y,z),y_correct))

2   Pass
x = true; y = true; z = true; y_correct = ((x&y)|z)&((z|x&y)|(z&y|x))|((x&z)|z)&((y|x&z)|(z&x|y))|(x|y|z); assert(isequal(your_fcn_name(x,y,z),y_correct))

3   Pass
x = true; y = false; z = false; y_correct = ((x&y)|z)&((z|x&y)|(z&y|x))|((x&z)|z)&((y|x&z)|(z&x|y))|(x|y|z); assert(isequal(your_fcn_name(x,y,z),y_correct))

4   Pass
x = false; y = false; z = true; y_correct = ((x&y)|z)&((z|x&y)|(z&y|x))|((x&z)|z)&((y|x&z)|(z&x|y))|(x|y|z); assert(isequal(your_fcn_name(x,y,z),y_correct))

5   Pass
x = false; y = false; z = false; y_correct = ((x&y)|z)&((z|x&y)|(z&y|x))|((x&z)|z)&((y|x&z)|(z&x|y))|(x|y|z); assert(isequal(your_fcn_name(x,y,z),y_correct))