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good catch (this solution would fail on '~A')
Test | Status | Code Input and Output |
---|---|---|
1 | Pass |
x = '0';
y_correct = false;
assert(isequal(tautology(x),y_correct))
|
2 | Pass |
x = '1';
y_correct = true;
assert(isequal(tautology(x),y_correct))
|
3 | Pass |
x = 'A';
y_correct = false;
assert(isequal(tautology(x),y_correct))
|
4 | Fail |
x = '~A';
y_correct = false;
assert(isequal(tautology(x),y_correct))
|
5 | Pass |
x = 'A|1';
y_correct = true;
assert(isequal(tautology(x),y_correct))
|
6 | Pass |
x = '1&A';
y_correct = false;
assert(isequal(tautology(x),y_correct))
|
7 | Pass |
x = 'A|B';
y_correct = false;
assert(isequal(tautology(x),y_correct))
|
8 | Pass |
x = 'A&B';
y_correct = false;
assert(isequal(tautology(x),y_correct))
|
9 | Pass |
x = 'A|A';
y_correct = false;
assert(isequal(tautology(x),y_correct))
|
10 | Pass |
x = 'A|~A';
y_correct = true;
assert(isequal(tautology(x),y_correct))
|
11 | Pass |
x = '0==0';
y_correct = true;
assert(isequal(tautology(x),y_correct))
|
12 | Pass |
x = '~0';
y_correct = true;
assert(isequal(tautology(x),y_correct))
|
13 | Pass |
x = '~(A & B) == (~A | ~B)';
y_correct = true;
assert(isequal(tautology(x),y_correct))
|
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