Cody

# Problem 582. Function composition - harder

Solution 459787

Submitted on 21 Jun 2014 by rifat
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### Test Suite

Test Status Code Input and Output
1   Pass
%% f1 = @(x)x+1; f2 = @(x)3*x; f3 = @sqrt; h = compose(f1,f2,f3); assert(isequal(h(9),10));

a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x))

2   Pass
%% f = repmat({@(x)x+1},1,100); h = compose(f{:}); assert(isequal(h(0),100));

a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x)) a = @(x)a(p(x))

3   Pass
%% f = @(x)x; h = compose(f); assert(isequal(h(1234),1234));

a = @(x)a(p(x))