Cody

# Problem 71. Read a column of numbers and interpolate missing data

Solution 1699802

Submitted on 27 Dec 2018 by Silas Henderson
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### Test Suite

Test Status Code Input and Output
1   Pass
s = { ... 'Day Temp' ' 1 1.3' ' 2 1.12' ' 3 17' ' 4 -32' ' 5 13' ' 6 4.4' ' 7 19'}; t_correct = [1.3 1.12 17 -32 13 4.4 19]; assert(isequal(read_and_interp(s),t_correct));

base9 = 0×1 empty double column vector stepSize = [] t = 1.3000 1.1200 17.0000 -32.0000 13.0000 4.4000 19.0000

2   Pass
s = { ... 'Day Temp' ' 1 1.3' ' 2 1.12' ' 3 17' ' 4 16' ' 5 9999' ' 6 9999' ' 7 19'}; t_correct = [1.3 1.12 17 16 17 18 19]; assert(isequal(read_and_interp(s),t_correct));

base9 = 16 stepSize = 1 data = 1.0e+03 * 0.0010 0.0013 0.0020 0.0011 0.0030 0.0170 0.0040 0.0160 0.0050 0.0170 0.0060 9.9990 0.0070 0.0190 data = 1.0000 1.3000 2.0000 1.1200 3.0000 17.0000 4.0000 16.0000 5.0000 17.0000 6.0000 18.0000 7.0000 19.0000 t = 1.3000 1.1200 17.0000 16.0000 17.0000 18.0000 19.0000

3   Pass
s = { ... 'Day Temp' ' 1 -5' ' 2 19' ' 3 1' ' 4 9999' ' 5 3'}; t_correct = [-5 19 1 2 3]; assert(isequal(read_and_interp(s),t_correct));

base9 = 1 stepSize = 1 data = 1 -5 2 19 3 1 4 2 5 3 t = -5 19 1 2 3

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