Cody

# Problem 794. Matrix with different incremental runs

Solution 262344

Submitted on 17 Jun 2013 by Dan
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.

### Test Suite

Test Status Code Input and Output
1   Pass
%% a = [ 3 2 4 ]; b = [ 1 1 1 2 2 2 3 0 3 0 0 4 ]; assert(isequal(your_fcn_name(a),b))

ans = 1 2 3 b = 1 0 0 2 0 0 3 0 0 0 0 0 ans = 1 2 b = 1 1 0 2 2 0 3 0 0 0 0 0 ans = 1 2 3 4 b = 1 1 1 2 2 2 3 0 3 0 0 4

2   Pass
%% a = [1 0 8 9 14]; b =[ 1 0 1 1 1 0 0 2 2 2 0 0 3 3 3 0 0 4 4 4 0 0 5 5 5 0 0 6 6 6 0 0 7 7 7 0 0 8 8 8 0 0 0 9 9 0 0 0 0 10 0 0 0 0 11 0 0 0 0 12 0 0 0 0 13 0 0 0 0 14]; assert(isequal(your_fcn_name(a),b))

ans = 1 b = 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ans = Empty matrix: 0-by-1 b = 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ans = 1 2 3 4 5 6 7 8 b = 1 0 1 0 0 0 0 2 0 0 0 0 3 0 0 0 0 4 0 0 0 0 5 0 0 0 0 6 0 0 0 0 7 0 0 0 0 8 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ans = 1 2 3 4 5 6 7 8 9 b = 1 0 1 1 0 0 0 2 2 0 0 0 3 3 0 0 0 4 4 0 0 0 5 5 0 0 0 6 6 0 0 0 7 7 0 0 0 8 8 0 0 0 0 9 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ans = 1 2 3 4 5 6 7 8 9 10 11 12 13 14 b = 1 0 1 1 1 0 0 2 2 2 0 0 3 3 3 0 0 4 4 4 0 0 5 5 5 0 0 6 6 6 0 0 7 7 7 0 0 8 8 8 0 0 0 9 9 0 0 0 0 10 0 0 0 0 11 0 0 0 0 12 0 0 0 0 13 0 0 0 0 14

3   Pass
%% a = [ 4 2 4 ]; b =[ 1 1 1 2 2 2 3 0 3 4 0 4]; assert(isequal(your_fcn_name(a),b))

ans = 1 2 3 4 b = 1 0 0 2 0 0 3 0 0 4 0 0 ans = 1 2 b = 1 1 0 2 2 0 3 0 0 4 0 0 ans = 1 2 3 4 b = 1 1 1 2 2 2 3 0 3 4 0 4

4   Pass
%% one value a= 1; assert(isequal(your_fcn_name(a),1))

ans = 1 b = 1

5   Pass
%% empty vector a = []; assert(isequal(your_fcn_name(a),[]))