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Let's see together.","description":"Referring to problem:\r\n\r\nhttps://www.mathworks.com/matlabcentral/cody/problems/44530-are-you-more-familiar-with-iteration-methods-or-linear-algebra-let-s-see-together\r\n\r\nGiven a sum result *_x_* value of a *_N_* number of addends, build an array of _*N*_ elements _*y*_ such that the following equality is satisfied: _sum(y) = x_ .\r\n\r\nFor example if: x = 10 and N = 2, possible solutions for y are: [7 3], or  [8 2].\r\n\r\nMore formally if x = a and N = n it results: \r\n\r\ny = [y_1 y_2 y_3 ... y_n]\r\nwhere:  y_1 + y_2 + y_3 +...+ y_n = a\r\n\r\nImportant notice: All the elements in y must be: *different from zero*, *different from each other* and *strictly positive* . On the other hand I will not take into account if they are _integers or decimal numbers_ .\r\n\r\nHint: You can use several approaches and the solution is not unique. For example you can think to approach with a iterative method or, if you are more accustomed with Algebra, by solving a linear system. This choice it's up to you.\r\n\r\nGood luck and enjoy with the solution ;)","description_html":"\u003cp\u003eReferring to problem:\u003c/p\u003e\u003cp\u003ehttps://www.mathworks.com/matlabcentral/cody/problems/44530-are-you-more-familiar-with-iteration-methods-or-linear-algebra-let-s-see-together\u003c/p\u003e\u003cp\u003eGiven a sum result \u003cb\u003e\u003ci\u003ex\u003c/i\u003e\u003c/b\u003e value of a \u003cb\u003e\u003ci\u003eN\u003c/i\u003e\u003c/b\u003e number of addends, build an array of \u003ci\u003e\u003cb\u003eN\u003c/b\u003e\u003c/i\u003e elements \u003ci\u003e\u003cb\u003ey\u003c/b\u003e\u003c/i\u003e such that the following equality is satisfied: \u003ci\u003esum(y) = x\u003c/i\u003e .\u003c/p\u003e\u003cp\u003eFor example if: x = 10 and N = 2, possible solutions for y are: [7 3], or  [8 2].\u003c/p\u003e\u003cp\u003eMore formally if x = a and N = n it results:\u003c/p\u003e\u003cp\u003ey = [y_1 y_2 y_3 ... y_n]\r\nwhere:  y_1 + y_2 + y_3 +...+ y_n = a\u003c/p\u003e\u003cp\u003eImportant notice: All the elements in y must be: \u003cb\u003edifferent from zero\u003c/b\u003e, \u003cb\u003edifferent from each other\u003c/b\u003e and \u003cb\u003estrictly positive\u003c/b\u003e . On the other hand I will not take into account if they are \u003ci\u003eintegers or decimal numbers\u003c/i\u003e .\u003c/p\u003e\u003cp\u003eHint: You can use several approaches and the solution is not unique. For example you can think to approach with a iterative method or, if you are more accustomed with Algebra, by solving a linear system. This choice it's up to you.\u003c/p\u003e\u003cp\u003eGood luck and enjoy with the solution ;)\u003c/p\u003e","function_template":"function y = buildSumArray(x,N);\r\n  y = sum(1:N);\r\nend","test_suite":"%% Test Case 1\r\nx = 6;\r\nN = 3;\r\ny = buildSumArray(x,N);\r\ny2 = unique(y);\r\n\r\nassert(isequal(round(sum(y)*100)/100,x))\r\nassert(isequal(length(y),N))\r\nassert(isequal(length(y2),N))\r\nassert(sum(y == 0) == 0)\r\nassert(isempty(y(y \u003c 0)))\r\n\r\n%% Test Case 2\r\nx = 13;\r\nN = 5;\r\ny = buildSumArray(x,N);\r\ny2 = unique(y);\r\n\r\nassert(isequal(round(sum(y)*100)/100,x))\r\nassert(isequal(length(y),N))\r\nassert(isequal(length(y2),N))\r\nassert(sum(y == 0) == 0)\r\nassert(isempty(y(y \u003c 0)))\r\n\r\n%% Test Case 3\r\nx = 78;\r\nN = 11;\r\ny = buildSumArray(x,N);\r\ny2 = unique(y);\r\n\r\nassert(isequal(round(sum(y)*100)/100,x))\r\nassert(isequal(length(y),N))\r\nassert(isequal(length(y2),N))\r\nassert(sum(y == 0) == 0)\r\nassert(isempty(y(y \u003c 0)))\r\n\r\n%% 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0)))\r\n","published":true,"deleted":false,"likes_count":2,"comments_count":3,"created_by":181340,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":25,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":677,"created_at":"2018-02-24T14:17:32.000Z","updated_at":"2026-03-05T10:42:37.000Z","published_at":"2018-02-24T14:18:32.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eReferring to problem:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:hyperlink w:docLocation=\\\"https://www.mathworks.com/matlabcentral/cody/problems/44530-are-you-more-familiar-with-iteration-methods-or-linear-algebra-let-s-see-together\\\"\u003e\u003cw:r\u003e\u003cw:t\u003ehttps://www.mathworks.com/matlabcentral/cody/problems/44530-are-you-more-familiar-with-iteration-methods-or-linear-algebra-let-s-see-together\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eGiven a sum result\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ex\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e value of a\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eN\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e number of addends, build an array of\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eN\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e elements\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ey\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e such that the following equality is satisfied:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003esum(y) = x\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e .\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor example if: x = 10 and N = 2, possible solutions for y are: [7 3], or [8 2].\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eMore formally if x = a and N = n it results:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ey = [y_1 y_2 y_3 ... y_n] where: y_1 + y_2 + y_3 +...+ y_n = a\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eImportant notice: All the elements in y must be:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003edifferent from zero\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e,\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003edifferent from each other\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e and\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003estrictly positive\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e . On the other hand I will not take into account if they are\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eintegers or decimal numbers\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e .\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eHint: You can use several approaches and the solution is not unique. For example you can think to approach with a iterative method or, if you are more accustomed with Algebra, by solving a linear system. This choice it's up to you.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eGood luck and enjoy with the solution ;)\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"errors":[],"problems":[{"id":44531,"title":"2) Are you more familiar with iteration methods or Linear Algebra ? Let's see together.","description":"Referring to problem:\r\n\r\nhttps://www.mathworks.com/matlabcentral/cody/problems/44530-are-you-more-familiar-with-iteration-methods-or-linear-algebra-let-s-see-together\r\n\r\nGiven a sum result *_x_* value of a *_N_* number of addends, build an array of _*N*_ elements _*y*_ such that the following equality is satisfied: _sum(y) = x_ .\r\n\r\nFor example if: x = 10 and N = 2, possible solutions for y are: [7 3], or  [8 2].\r\n\r\nMore formally if x = a and N = n it results: \r\n\r\ny = [y_1 y_2 y_3 ... y_n]\r\nwhere:  y_1 + y_2 + y_3 +...+ y_n = a\r\n\r\nImportant notice: All the elements in y must be: *different from zero*, *different from each other* and *strictly positive* . On the other hand I will not take into account if they are _integers or decimal numbers_ .\r\n\r\nHint: You can use several approaches and the solution is not unique. For example you can think to approach with a iterative method or, if you are more accustomed with Algebra, by solving a linear system. This choice it's up to you.\r\n\r\nGood luck and enjoy with the solution ;)","description_html":"\u003cp\u003eReferring to problem:\u003c/p\u003e\u003cp\u003ehttps://www.mathworks.com/matlabcentral/cody/problems/44530-are-you-more-familiar-with-iteration-methods-or-linear-algebra-let-s-see-together\u003c/p\u003e\u003cp\u003eGiven a sum result \u003cb\u003e\u003ci\u003ex\u003c/i\u003e\u003c/b\u003e value of a \u003cb\u003e\u003ci\u003eN\u003c/i\u003e\u003c/b\u003e number of addends, build an array of \u003ci\u003e\u003cb\u003eN\u003c/b\u003e\u003c/i\u003e elements \u003ci\u003e\u003cb\u003ey\u003c/b\u003e\u003c/i\u003e such that the following equality is satisfied: \u003ci\u003esum(y) = x\u003c/i\u003e .\u003c/p\u003e\u003cp\u003eFor example if: x = 10 and N = 2, possible solutions for y are: [7 3], or  [8 2].\u003c/p\u003e\u003cp\u003eMore formally if x = a and N = n it results:\u003c/p\u003e\u003cp\u003ey = [y_1 y_2 y_3 ... y_n]\r\nwhere:  y_1 + y_2 + y_3 +...+ y_n = a\u003c/p\u003e\u003cp\u003eImportant notice: All the elements in y must be: \u003cb\u003edifferent from zero\u003c/b\u003e, \u003cb\u003edifferent from each other\u003c/b\u003e and \u003cb\u003estrictly positive\u003c/b\u003e . On the other hand I will not take into account if they are \u003ci\u003eintegers or decimal numbers\u003c/i\u003e .\u003c/p\u003e\u003cp\u003eHint: You can use several approaches and the solution is not unique. For example you can think to approach with a iterative method or, if you are more accustomed with Algebra, by solving a linear system. This choice it's up to you.\u003c/p\u003e\u003cp\u003eGood luck and enjoy with the solution ;)\u003c/p\u003e","function_template":"function y = buildSumArray(x,N);\r\n  y = sum(1:N);\r\nend","test_suite":"%% Test Case 1\r\nx = 6;\r\nN = 3;\r\ny = buildSumArray(x,N);\r\ny2 = unique(y);\r\n\r\nassert(isequal(round(sum(y)*100)/100,x))\r\nassert(isequal(length(y),N))\r\nassert(isequal(length(y2),N))\r\nassert(sum(y == 0) == 0)\r\nassert(isempty(y(y \u003c 0)))\r\n\r\n%% Test Case 2\r\nx = 13;\r\nN = 5;\r\ny = buildSumArray(x,N);\r\ny2 = unique(y);\r\n\r\nassert(isequal(round(sum(y)*100)/100,x))\r\nassert(isequal(length(y),N))\r\nassert(isequal(length(y2),N))\r\nassert(sum(y == 0) == 0)\r\nassert(isempty(y(y \u003c 0)))\r\n\r\n%% Test Case 3\r\nx = 78;\r\nN = 11;\r\ny = buildSumArray(x,N);\r\ny2 = unique(y);\r\n\r\nassert(isequal(round(sum(y)*100)/100,x))\r\nassert(isequal(length(y),N))\r\nassert(isequal(length(y2),N))\r\nassert(sum(y == 0) == 0)\r\nassert(isempty(y(y \u003c 0)))\r\n\r\n%% Test Case 4\r\nx = 2689;\r\nN = 245;\r\ny = buildSumArray(x,N);\r\ny2 = unique(y);\r\n\r\nassert(isequal(round(sum(y)*100)/100,x))\r\nassert(isequal(length(y),N))\r\nassert(isequal(length(y2),N))\r\nassert(sum(y == 0) == 0)\r\nassert(isempty(y(y \u003c 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version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eReferring to problem:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:hyperlink w:docLocation=\\\"https://www.mathworks.com/matlabcentral/cody/problems/44530-are-you-more-familiar-with-iteration-methods-or-linear-algebra-let-s-see-together\\\"\u003e\u003cw:r\u003e\u003cw:t\u003ehttps://www.mathworks.com/matlabcentral/cody/problems/44530-are-you-more-familiar-with-iteration-methods-or-linear-algebra-let-s-see-together\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:hyperlink\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eGiven a sum result\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ex\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e value of a\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eN\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e number of addends, build an array of\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eN\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e elements\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003ey\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e such that the following equality is satisfied:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003esum(y) = x\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e .\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor example if: x = 10 and N = 2, possible solutions for y are: [7 3], or [8 2].\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eMore formally if x = a and N = n it results:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ey = [y_1 y_2 y_3 ... y_n] where: y_1 + y_2 + y_3 +...+ y_n = a\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eImportant notice: All the elements in y must be:\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003edifferent from zero\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e,\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003edifferent from each other\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e and\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:b/\u003e\u003c/w:rPr\u003e\u003cw:t\u003estrictly positive\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e . On the other hand I will not take into account if they are\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e \u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:rPr\u003e\u003cw:i/\u003e\u003c/w:rPr\u003e\u003cw:t\u003eintegers or decimal numbers\u003c/w:t\u003e\u003c/w:r\u003e\u003cw:r\u003e\u003cw:t\u003e .\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eHint: You can use several approaches and the solution is not unique. For example you can think to approach with a iterative method or, if you are more accustomed with Algebra, by solving a linear system. 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