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using a for loop for dynamic indexing of a structure
turns out that ii becomes a cell containing the string in the first version and not the string itself. That's why it's not worki...
13 years ago | 1
| accepted
Question
using a for loop for dynamic indexing of a structure
Hello, I am wondering why this does not work? t.order = {'x1' 'x2' 'x3'}; t.x1 = 1; t.x2 = 2; t.x3 = 3; ...
13 years ago | 1 answer | 0