|
|
|
| R2012a Documentation → MATLAB | |
Learn more about MATLAB |
|
| Contents | Index |
[uout,duoutdx] = pdeval(m,x,ui,xout)
Symmetry of the problem: slab = 0, cylindrical = 1, spherical = 2. This is the first input argument used in the call to pdepe. | |
A vector [x0, x1, ..., xn] specifying the points at which the elements of ui were computed. This is the same vector with which pdepe was called. | |
A vector sol(j,:,i) that approximates component i of the solution at time tf and mesh points xmesh, where sol is the solution returned by pdepe. | |
A vector of points from the interval [x0,xn] at which the interpolated solution is requested. |
[uout,duoutdx] = pdeval(m,x,ui,xout) approximates the solution ui and its partial derivative ∂ui/∂x at points from the interval [x0,xn]. The pdeval function returns the computed values in uout and duoutdx, respectively.
Note pdeval evaluates the partial derivative ∂ui/∂x rather than the flux f. Although the flux is continuous, the partial derivative may have a jump at a material interface. |
Explore how to use MATLAB to make advancements in engineering and science.
| © 1984-2012- The MathWorks, Inc. - Site Help - Patents - Trademarks - Privacy Policy - Preventing Piracy - RSS |