lsqnonlin: units of functions

As explained in help, I created a vector-valued function f(x)=[f1;...;fn]. But the functions have different Units. E.g.

[f1]=m,
[f2]=m/s,
[f3]=rad/s,
...

Is this a Problem?

Answer 1

[Torsten]

Say you have two functions given as

f1 = 3000*x - 20
f2 = 3*x - 0.03

and you use lsqnonlin to determine x.

What do you think ? Will the solution be closer to 20/3000 or 0.03/3 ?

Best wishes

Torsten.