lsqnonlin: units of functions
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As explained in help, I created a vector-valued function f(x)=[f1;...;fn]. But the functions have different Units. E.g.
[f1]=m,
[f2]=m/s,
[f3]=rad/s,
...
Is this a Problem?
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Accepted Answer
Torsten
on 30 May 2018
Say you have two functions given as
f1 = 3000*x - 20
f2 = 3*x - 0.03
and you use lsqnonlin to determine x.
What do you think ? Will the solution be closer to 20/3000 or 0.03/3 ?
Best wishes
Torsten.
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