Code covered by the BSD License
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ITUP1546(varargin)
ITUP1546 M-file for ITUP1546.fig
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D06(f,h1,h2)
17 An approximation to the 0.6 Fresnel clearance path length
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Emax(d,t,path)
2 Maximum field-strength values
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FindDNominals(d)
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P1546FieldStr(d,f,t,heff,vara...
P1546FieldStr ITU 1546-3 Field strength calculator
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P1546FieldStrbeta(d,f,t,heff,...
P1546FieldStr ITU 1546-3 Field strength calculator
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Qi(x)
15 An approximation to the inverse complementary cumulative normal distribution
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Step_12(f,tca)
Step 12: If information on the terrain clearance angle at a
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Step_13(d,f,t,eff,eff1)
Step 13: Calculate the estimated field strength due to tropospheric
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Step_14(h2,f,path,varargin)
Step 14: Correct the field strength for receiving/mobile antenna height
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Step_15(d,h1,ha,f,env)
Step 15: If applicable, reduce the field strength by adding the
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Step_16()
Step 16: If the field strength at a receiving/mobile antenna adjacent to
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Step_17(E,Efs,Ese,ds,dtotal)
Step 17: If necessary, limit the resulting field strength to the maximum
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Step_18(fs,f)
Step 18: If required, convert field strength to equivalent basic transmission loss for the path using
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V(Kv,h1)
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d =FS_find_dnew(FS,f,heff,T,p...
FS_FIND_D ITU 1546 Field strength calculator: Find d for known Fieldstrength
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find_d(FS,f,heff,T,path,h2)
Peverted code the code find the closest value d value that equates the
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h1Calc(d,heff,ha,hb,path)
3 Determination of transmitting/base antenna height, h1
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h2corr(h2,f,varargin)
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searchclosest(x,v)
The following code tidbit is by Dr. Murtaza Khan, modified to return
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step6_10(figure,h1,dinf,dsup,...
function E = step6_10(figure,h1,dinf,dsup,d,path,f,Emaxvalue,t)
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step7_normal(figureStep6,h1,d...
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step81(tabulatedValues,h1,din...
Step 8: Obtain the field strength exceeded at 50% locations for a
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step814_815(tabulatedValues,h...
Step 8.1.4: Obtain the field strength exceeded at 50% locations
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step82(tabulatedValues,h1,din...
Step 8.2: For a transmitting/base antenna height h1 less than 10 m
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P1546validation.m
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Test_D06.m
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Test_Emax.m
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Test_FindDNominals.m
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Test_P1546FieldStr.m
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Test_Qi.m
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Test_V.m
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Test_h1Calc.m
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Test_searchclosest.m
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Test_step6_10.m
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Test_step7_normal.m
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Test_step81.m
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Test_step814_815.m
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Test_step82.m
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View all files
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ITU-R p.1546 calculator
by Jef Statham
This an implementation of the ITU-R p.1546 model. Mixed land a sea paths not implemented.
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| D06(f,h1,h2)
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% 17 An approximation to the 0.6 Fresnel clearance path length
% The path length which just achieves a clearance of 0.6 of the first
% Fresnel zone over a smooth curved Earth, for a given frequency and
% antenna heights h1 and h2, is given approximately by:
% some formula (38)
% where:
% Df : frequency-dependent term
% = 0.0000389 f h1h2 km (39a)
% Dh : asymptotic term defined by horizon distances
% = 4.1( h1+ h2 ) km (39b)
% f : frequency (MHz)
% h1, h2 : antenna heights above smooth Earth (m).
% In the above equations, the value of h1 must be limited, if necessary,
% such that it is not less than zero. Moreover, the resulting values of D06
% must be limited, if necessary, such that it is not less than 0.001 km.
function D = D06(f,h1,h2)
Df = 0.0000389*f*h1*h2; % equ'n (39a)
Dh = 4.1*(sqrt(h1)+sqrt(h2)); % equ'n (39b)
D = Df*Dh/(Df+Dh); % equ'n (38)
if D < 0.001
D = 0.001;
end
end
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