Code covered by the BSD License

### Highlights fromMatlab code for my Graduate Thesis

from Matlab code for my Graduate Thesis by Troy
Numerically solves the diffusion equations as it pertains to medical imaging.

rk42Dsliding(varargin)
```function w = rk42Dsliding(varargin)
% crankNicolson: uses Crank-Nicolson algorithm to approximate the solution
%   to the parabolic PDE:
%       u_{t}(x,t) - alpha^2 u_{xx}(x,t) = 0, 0<x<L, 0<t<T
%   subject to the boundary conditions
%       u(0,t) = u(L,t) = 0, 0<t<T
%   and the initial conditions
%       u(x,0) = f(x), 0<=x<=L
%
% arguments:
%   L (vector 1by2) - upper bound of spatial (x) variable
%       (Default L = [1,1])
%   T (scalar) - upper bound of time (t) variable
%       (Default T = 1)
%   alpha (scalar) - square root of coefficient of u_{xx} term
%       (Default alpha = 1)
%   m (vector 1by2) - number of discrete spatial intervals
%       (Default m = [100,100])
%   n (scalar) - number of discrete time intervals
%       (Default n = 100)
%
%   w (m+1 x m+1 x n) - approximation to u(x,t) at discrete space/time positions
%

% author: Troy J. Winkstern
% email: tjw8191@rit.edu
% date: 30 Jan 2011

% parse input arguments
[L,T,alpha,m,n] = parseInputs(varargin{:});
L_x = L(1);
L_y = L(2);
m_x = m(1);
m_y = m(2);

% initialize h, k, lambda, and w
h_x = L_x/m_x;
h_y = L_y/m_y;
k = (T./n).^2;
lambda_x = (alpha.^2).*k./(h_x.^2);
lambda_y = (alpha.^2).*k./(h_y.^2);
w = zeros(2*m_y+1,m_x+1,n);

% initialize w (change this to sin(pix/l)*cos(piy/l)
for i=1:m_x+1
for j=1:2*m_y+1
w(j,i,1) = sin(pi.*h_x.*(i-1)./L_x).*cos(pi.*h_y.*(j-1)./L_y);
end
end

for t=1:(n-1)
f = (alpha^2)*laplacian(w(:,:,t),h_y,h_x);
K_1 = k*f;

g1 = w(:,:,t) + ((K_1)/2);
K_2 = k*(alpha^2)*laplacian(g1,h_y,h_x);
g2 = w(:,:,t) + K_2/2;
K_3 = k*(alpha^2)*laplacian(g2,h_y,h_x);
g3 = w(:,:,t) + K_3;
K_4 = k*(alpha^2)*laplacian(g3,h_y,h_x);

rhs = w(:,:,t) + (1/6)*(K_1 + 2*K_2 + 2*K_3 + K_4);

% went out to length 2m
X = sqrt(2./m_x).*imag(fft(rhs, 2*m_x,2));
X = X(:,1:m_x+1);

Y = [sqrt(1./(2*m_y)).*real(fft(X,2*m_y,1));zeros(1,m_x+1)];

% angles divided by m
a_x = repmat((pi./m_x).*(0:m_x),[2*m_y+1 1]);
a_y = repmat((pi./m_y).*(0:2*m_y).',[1 m_x+1]);

% changed lambda to negative
c = 1 + (((lambda_x)*(h_x)^2)*((lambda_y)*(h_y)^2))+ (1/6)*...
(((lambda_x)*cos(a_x)*(h_x)^2).*((lambda_y)*cos(a_y)*(h_y)^2));

% went out to length 2m
Z = sqrt(2./m_x).*imag(fft(Y./c, 2*m_x,2));
Z = Z(:,1:m_x+1);

R = sqrt(1./(2*m_y)).*real(fft(Z, 2*m_y,1));
R = R([1:2*m_y 1],:);

w(:,:,t+1) = R;

end

%crop w
w = w(1:m_y+1,1:m_x+1,:);

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% subfunction parseInputs
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
function [L,T,alpha,m,n] = parseInputs(varargin)

% check number of input arguments
nargs = length(varargin);
error(nargchk(0,5,nargs));

% get/set n
if nargs<5
n = [];
else
n = varargin{5};
end
if isempty(n)
n = 100;
end

% check n has valid value
if (numel(n)>1) || (n<1) || ~isequal(round(n),n)
error('n must be a positive integer.');
end

% get/set m
if nargs<4
m = [];
else
m = varargin{4};
end
if isempty(m)
m = [100,100];
end

% check m has valid value
if (numel(m)~=2) || any(m<1) || any(~isequal(round(m),m))
error('m must be a vector of positive integers.');
end

% get/set alpha
if nargs<3
alpha = [];
else
alpha = varargin{3};
end
if isempty(alpha)
alpha = 1;
end

% check alpha has valid value
if numel(alpha)>1
error('alpha must be a real scalar.');
end

% get/set T
if nargs<2
T = [];
else
T = varargin{2};
end
if isempty(T)
T = 1;
end

% check T has valid value
if (numel(T)>1) || (T<=0)
error('T must be a positive real scalar.');
end

% get/set L
if nargs<1
L = [];
else
L = varargin{1};
end
if isempty(L)
L = [1,1];
end

% check L has valid value
if (numel(L)~=2) || any(L<=0)
error('L must be a positive vector with 2 elements.');
end

% warning if L not integer
if any(~isequal(round(L),L))
warning('L should be an vector of integers so that the inital condition takes on the value of 0 for t = 0 and t = T.');
endarning('L should be an integer so that the inital condition takes on the value of 0 for t = 0 and t = T.');
end

%another subfunction
function y = laplacian(x,h_y,h_x)
[m,n] = size(x);
y = zeros(m,n);

for i = 2:n-1
y(1,i) = (x(1,i+1)-2*x(1,i)+x(1,i-1))/(h_x.^2)+(2*x(2,i)-2*x(1,i))/(h_y.^2);
end

for i = 2:n-1
for j = 2:m-1

y(j,i) = (x(j-1,i)+x(j+1,i)-2*x(j,i))/(h_y.^2)+(x(j,i-1)+x(j,i+1)-2*x(j,i))/(h_x.^2);

end
end

for i = 2:n-1
y(m,i) = (x(m,i+1)-2*x(m,i)+x(m,i-1))/(h_x.^2)+(2*x(m-1,i)-2*x(m,i))/(h_y.^2);
end```