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2D Line Curvature and Normals

4.6 | 5 ratings Rate this file 117 Downloads (last 30 days) File Size: 8.97 KB File ID: #32696 Version: 1.3
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2D Line Curvature and Normals


Dirk-Jan Kroon (view profile)


26 Aug 2011 (Updated )

Accurate Curvature and Normals of a line/contour consisting of 2D points

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LineCurvature2D, This function calculates the curvature of a 2D line. It first fits polygons to the points. Then calculates the analytical curvature from the polygons.
   K = LineCurvature2D(Vertices,Lines)
    Vertices : A M x 2 list of line points.
    Lines : A N x 2 list of line pieces, by indices of the vertices
          (if not set assume Lines=[1 2; 3 4 ; ... ; M-1 M])
    K : M x 1 Curvature values

LineNormals2D, This function calculates the normals, of the line. Using the neighbouring points of each line/contour point, and forward an backward differences on the end points

    V : List of points/vertices 2 x M
    Lines : A N x 2 list of line pieces, by indices of the vertices
          (if not set assume Lines=[1 2; 3 4 ; ... ; M-1 M])
    N : The normals of the Vertices 2 x M


This file inspired Thick Line(X,Y,Thickness).

MATLAB release MATLAB 7.12 (R2011a)
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Comments and Ratings (8)
23 Jun 2015 Robbin van Hoek

From what i understand the algorithm only uses the direct neighbors of the point to be evaluated correct? is it possible to include multiple nearby points to get a more accurate result?

12 Mar 2015 Khalid Ali

What is meant by lines?

Comment only
12 Jan 2015 rabeeah

very useful code. i would also like to know the mathematical model used. does it use the freeman chain code Dirk?

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29 Aug 2014 Michael

Thank you, good code to find in my case finger tips on a hand scan

18 Feb 2014 Yunfeng  
08 Jul 2013 Simon

Simon (view profile)

Is there any literature to back this up??
Also, the grammar in the comments needs serious work....

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18 Jan 2013 Willy

Willy (view profile)

Thank you! Very usefull code! I would like to understand the maths behind the code better. Is this code based on some literature?

15 Oct 2011 Ravikiran Janardhana

I would like to point out a small typo:-
L=[(1:(size(V,1)-1))' (2:size(V,1))'];
In the code I saw,the above was :-
Lines=[(1:(size(Vertices,1)-1))' (2:size(Vertices,1))'];

17 Oct 2011 1.3

Corrected typo reported by Ravikiran Janardhana

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