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2D Line Curvature and Normals

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2D Line Curvature and Normals

by

Dirk-Jan Kroon (view profile)

 

26 Aug 2011 (Updated )

Accurate Curvature and Normals of a line/contour consisting of 2D points

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Description

LineCurvature2D, This function calculates the curvature of a 2D line. It first fits polygons to the points. Then calculates the analytical curvature from the polygons.
 
   K = LineCurvature2D(Vertices,Lines)
  
  inputs,
    Vertices : A M x 2 list of line points.
    (optional)
    Lines : A N x 2 list of line pieces, by indices of the vertices
          (if not set assume Lines=[1 2; 3 4 ; ... ; M-1 M])
 
  outputs,
    K : M x 1 Curvature values

.
.
LineNormals2D, This function calculates the normals, of the line. Using the neighbouring points of each line/contour point, and forward an backward differences on the end points

  N=LineNormals2D(V,L)
 
  inputs,
    V : List of points/vertices 2 x M
  (optional)
    Lines : A N x 2 list of line pieces, by indices of the vertices
          (if not set assume Lines=[1 2; 3 4 ; ... ; M-1 M])
 
  outputs,
    N : The normals of the Vertices 2 x M
 

MATLAB release MATLAB 7.12 (R2011a)
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Comments and Ratings (7)
12 Mar 2015 Khalid Ali

What is meant by lines?

Comment only
12 Jan 2015 rabeeah

very useful code. i would also like to know the mathematical model used. does it use the freeman chain code Dirk?

Comment only
29 Aug 2014 Michael

Thank you, good code to find in my case finger tips on a hand scan

18 Feb 2014 Yunfeng  
08 Jul 2013 Simon

Simon (view profile)

Is there any literature to back this up??
Also, the grammar in the comments needs serious work....

Comment only
18 Jan 2013 Willy

Willy (view profile)

Thank you! Very usefull code! I would like to understand the maths behind the code better. Is this code based on some literature?

15 Oct 2011 Ravikiran Janardhana

I would like to point out a small typo:-
*****(correct)****
if(nargin<2)
L=[(1:(size(V,1)-1))' (2:size(V,1))'];
end
*****
In the code I saw,the above was :-
*****(typo)*****
Lines=[(1:(size(Vertices,1)-1))' (2:size(Vertices,1))'];
*****

Updates
17 Oct 2011

Corrected typo reported by Ravikiran Janardhana

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