Read file
19 views (last 30 days)
Show older comments
Hi all,
probably a very simple question..I need to read a text file consisting of a list of vectors with this format:
skip the first 22 line and then (x y z) (x y z) (x y z) ... (x y z)
there are 263853 line. How can i do that??
thanks for any help
andrea
0 Comments
Answers (3)
Jan
on 15 Feb 2011
The description of the file format is not exact enough. I'll show you a method for a well defined format and I assume you can adjust it to your needs:
I assume the file looks like this:
Header line 1
...
Header line 22
(0.1 0.2 0.3)
(0.17 19.5 231)
... <263853 of such lines>
This can be solved by TEXTSCAN or more low-levelish:
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
for iSkip = 1:22
dummy = fgetl(FID);
end
Data = fscanf(FID, '(%g %g %g)\n');
Data = transpose(reshape(Data, 3, []));
fclose(FID);
2 Comments
Matt Tearle
on 15 Feb 2011
Or, using textscan (as Jan mentioned):
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
Data = textscan(FID, '(%f %f %f)','headerlines',22);
x = Data{1};
y = Data{2};
z = Data{3};
fclose(FID);
0 Comments
See Also
Categories
Find more on Text Data Preparation in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!