Read file

19 views (last 30 days)
Andrea Ferrari
Andrea Ferrari on 15 Feb 2011
Hi all,
probably a very simple question..I need to read a text file consisting of a list of vectors with this format:
skip the first 22 line and then (x y z) (x y z) (x y z) ... (x y z)
there are 263853 line. How can i do that??
thanks for any help
andrea

Answers (3)

Jan
Jan on 15 Feb 2011
The description of the file format is not exact enough. I'll show you a method for a well defined format and I assume you can adjust it to your needs:
I assume the file looks like this:
Header line 1
...
Header line 22
(0.1 0.2 0.3)
(0.17 19.5 231)
... <263853 of such lines>
This can be solved by TEXTSCAN or more low-levelish:
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
for iSkip = 1:22
dummy = fgetl(FID);
end
Data = fscanf(FID, '(%g %g %g)\n');
Data = transpose(reshape(Data, 3, []));
fclose(FID);
  2 Comments
Andrea Ferrari
Andrea Ferrari on 15 Feb 2011
thanks Jan. It runs
andrea
Jan
Jan on 15 Feb 2011
Thanking is very polite. Accpeting an answer is helpful for others in addition.

Sign in to comment.


Andrea Ferrari
Andrea Ferrari on 15 Feb 2011
sorry
all vector are in column (not along a line).
andrea

Matt Tearle
Matt Tearle on 15 Feb 2011
Or, using textscan (as Jan mentioned):
FID = fopen(FileName, 'r');
if FID <= 0, error('Cannot open file'); end
Data = textscan(FID, '(%f %f %f)','headerlines',22);
x = Data{1};
y = Data{2};
z = Data{3};
fclose(FID);

Categories

Find more on Text Data Preparation in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!