How to plot a function with 3 independent variables
126 views (last 30 days)
Show older comments
Seng Hkawn N-Sang
on 13 Oct 2021
Commented: Seng Hkawn N-Sang
on 15 Oct 2021
f(x,y,z)=0.95*x+0.73*y+0.62*z-130.05
f(x,y,z); x; y; and z are values between 0 and 100.
f(x,y,z) is shown in color. How can I plot in MATLAB similar to figure below.
Thank you!
1 Comment
Accepted Answer
KSSV
on 13 Oct 2021
f = @(x,y,z) 0.95*x+0.73*y+0.62*z-130.05 ;
x = linspace(0,100) ;
y = linspace(0,100) ;
z = linspace(0,100) ;
[X,Y,Z] = meshgrid(x,y,z) ;
V = f(X,Y,Z) ;
isosurface(X,Y,Z,V,1e-4)
6 Comments
Walter Roberson
on 14 Oct 2021
f = @(x,y,z) 0.95*x+0.73*y+0.62*z-130.05 ;
x = linspace(60,100) ;
y = linspace(60,100) ;
z = linspace(60,100) ;
[X,Y,Z] = meshgrid(x,y,z) ;
V = f(X,Y,Z) ;
Vmin = min(V(:))
Vmax = max(V(:))
levels = 70:5:100;
Nlevels = length(levels);
cmap = hot(Nlevels);
for K = 1 : Nlevels
s = isosurface(X, Y, Z, V, levels(K));
p(K) = patch(s);
p(K).EdgeColor = 'none';
p(K).FaceColor = cmap(K,:);
isonormals(X, Y, Z, V, p(K));
end
camlight;
lighting gouraud;
xlim auto; ylim auto; zlim auto
view(3); view(36, 64);
legend(p, string(levels))
You cannot do contour lines because you are dealing with a 3D object: you can only do ISO surfaces.
It might be possible to get the colors right without some of the above steps. With the default steps I showed in https://www.mathworks.com/matlabcentral/answers/1562461-how-to-plot-a-function-with-3-independent-variables#comment_1783116 you might notice that the colors come out wrong compared to the legend: it turns out that you are looking at the "back" of the plates, and that you need to view() to see the front (or you need to move the light.)
More Answers (0)
See Also
Categories
Find more on Lighting, Transparency, and Shading in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!