# Local Binary Pattern(LBP)

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C N N on 13 Sep 2011
Commented: Image Analyst on 16 Jul 2023
I am trying to execute local binary pattern in MATLAB using the image processing toolbox. When i execute I can't get a LBP image and LBP histogram.
clear all;
close all;
clc;
figure,imshow(I)
%%Crop
I2 = imcrop(I);
figure, imshow(I2)
w=size(I2,1);
h=size(I2,2);
%%LBP
scale = 2.^[7 6 5; 0 -inf 4; 1 2 3];
for i=2:w-1
for j=2:h-1
J0=I2(i,j);
I3(i-1,j-1)=I2(i-1,j-1)>J0;
I3(i-1,j)=I2(i-1,j)>J0;
I3(i-1,j+1)=I2(i-1,j+1)>J0;
I3(i,j+1)=I2(i,j+1)>J0;
I3(i+1,j+1)=I2(i+1,j+1)>J0;
I3(i+1,j)=I2(i+1,j)>J0;
I3(i+1,j-1)=I2(i+1,j-1)>J0;
I3(i,j-1)=I2(i,j-1)>J0;
LBP(i,j)=I3(i-1,j-1)*2^7+I3(i-1,j)*2^6+I3(i-1,j+1)*2^5+I3(i,j+1)*2^4+I3(i+1,j+1)*2^3+I3(i+1,j)*2^2+I3(i+1,j-1)*2^1+I3(i,j-1)*2^0;
end
end
figure,imshow(LBP)
figure,imhist(LBP)
what is the issue.i am supposed to get numbers from 0 to 255 but i am not getting it. how to correct it?
Image Analyst on 3 Feb 2019
Try
imshow(LBP, []);
and try my attached LBP demo.
sajjad nasiri on 28 May 2019

madhulika jain on 22 Sep 2011
I think you shpuld be getting LBP in the range 0 to 255. I ran this code and i got the values in this range only
C N N on 22 Sep 2011
The problem with this code that after you get LBP, you need to convert it to uint8 before displaying it.

Izzo on 3 Dec 2011
hey i think i got your problem, because i already did LBP. First, make sure that u have converted the image into grayscale form. Second, you have to replace the test image with the new LBP image, therefore: instead of this code
LBP(i,j)=I3(i-1,j-1)*2^7+I3(i-1,j)*2^6+I3(i-1,j+1)*2^5+I3(i,j+1)*2^4+I3(i+1,j+1)*2^3+I3(i+1,j)*2^2+I3(i+1,j-1)*2^1+I3(i,j-1)*2^0;
try to change into:
I2(i-1,j-1)=I3(i-1,j-1)*2^7+I3(i-1,j)*2^6+I3(i-1,j+1)*2^5+I3(i,j+1)*2^4+I3(i+1,j+1)*2^3+I3(i+1,j)*2^2+I3(i+1,j-1)*2^1+I3(i,j-1)*2^0;
because i have problem like that too, then my supervisor solve into this for me :P

Image Analyst on 22 Sep 2011
Change the last few lines of your code to this:
subplot(2,2,3);
imshow(LBP, []);
subplot(2,2,4);
[pixelCounts, GLs] = imhist(uint8(LBP));
bar(GLs, pixelCounts);
Fatemeh Shomal Zadeh on 13 Feb 2021
Hi,
I have a cell array data of grayscale images 20x5. (20 images at 5 frames)
I want to use LBP to analyze the background scatter points of my images and see if I can find any differences between their values, as my data covers the healthy and unhealthy patients.
Is there anyone who can help me for that. I have been using this code;
features = extractLBPFeatures(images{20,1})
subplot(2,2,3);
imshow(features, []);
subplot(2,2,4);
[pixelCounts, GLs] = imhist(uint8(features));
bar(GLs, pixelCounts);
But I think it does not show me what I want. As the output is a single array. I am not very familiar with LBP, can you please hep me regarding how the output should be?
Walter Roberson on 14 Feb 2021
But I think it does not show me what I want
We do not have your image to test with, and we do not know what kinds of output you expect to see.

remo on 1 Dec 2011
hi CNN,
Sorry for being a Noob. I just cant understand why you use 'scale = 2.^[7 6 5; 0 -inf 4; 1 2 3]; ' in this program. can you explain?
hi, I would like to know how did you get those number [ 7 6 5; 0 -inf 4; 1 2 3] ?
Did you calculate it?
Image Analyst on 29 Mar 2019
Unhide the comments above and you'll see a desciption of how those are computed.

anusha on 24 Sep 2014
Edited: DGM on 11 Feb 2023
u can try this code
clear all;
close all;
I=rgb2gray(I);
I1=imcrop(I);
[w h]=size(I1);
for i=2:w-1
for j=2:h-1
val=I1(i,j);
scale=2.^[0 1 2;7 -inf 3;6 5 4];
mat=[I1(i-1,j-1) I1(i-1,j) I1(i-1,j+1);
I1(i,j-1) I1(i,j) I1(i,j+1);
I1(i+1,j-1) I1(i+1,j) I1(i+1,j+1)];
mat=mat>=val;
fin=mat.*scale;
I1(i,j)=sum(sum(fin));
end
end
imshow(I1,[]);

Nikolay S. on 16 Mar 2015
You can try one of the following LBP implementations: http://www.mathworks.com/matlabcentral/fileexchange/49787-shift-based-lbp http://www.mathworks.com/matlabcentral/fileexchange/36484-local-binary-patterns I'm using both for a while, updating them fomr time to time.

Ktk on 29 Oct 2017
the code is not giving me any values. can anyone help? thanks!
##### 3 CommentsShow 1 older commentHide 1 older comment
SATISH SONWANE on 1 Jun 2022
Why did you use LSB?
Image Analyst on 1 Jun 2022
@SATISH SONWANE, isn't that the usual way? You can change it if you want. Why would you want to?

Vrushali Patil on 2 Apr 2020
Image Analyst on 2 Apr 2020
Who said you had to crop the image? Just go ahead and do it on your image without cropping it if you don't want to crop it. What's the problem?

Image Analyst on 2 Apr 2020
See my attached LBP demo.
##### 3 CommentsShow 1 older commentHide 1 older comment
PAVITHRA on 22 Feb 2023
If i run this demo code for brain tumor image,the lbp image becomes red color why?
Image Analyst on 22 Feb 2023
@PAVITHRA I have no idea what your code does. When anyone runs my code, this is what they'll see:
If you want me to look at your code, start a new question and attach your code and image.

Dehia on 15 Jul 2023
Is it normal to have a large number of zeros and a few non-zero values in the LBP feature array?
Image Analyst on 16 Jul 2023
For 3x3 submatrices where all the values are the same, you'd get zero. This can happen fairly often.

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