how to add one space to a matrix ?

am using this code to generate binary matrix dec2bin(rand(50,1)*2^32) but i need to add one space between the matrix element so i can use it for other commands. the output matrix needs space to be useful for other calculation. how to do this?

 Accepted Answer

Guillaume
Guillaume on 9 Nov 2014
Edited: Guillaume on 9 Nov 2014
The following would work:
m = dec2bin(rand(50,1)*2^32)
mwithspaces = cell2mat(regexprep(num2cell(m, 2),'\d(?=\d)', '$0 '));
I have to ask though, why do you want to do that? It seems like an unnecessary step. I would think that any algorithm that follows is probably going to remove these spaces one way or another.
edit: was missing a bracket

5 Comments

It gives a 2D character array, not a simple string. I think maybe he wants all those rows concatenated together with a space in between them.
In that case:
mwithspaces = regexprep(reshape(m', 1, []), '\d(?=\d)', '$0 '));
or
strjoin(num2cell(reshape(m', 1, [])), ' ');
But I still think that not doing this and changing the steps that follow to not require the spaces is probably a better idea.
I agree with you there.
As commented on Jan's answer, inserting spaces is a red herring. To convert a string of zeros and ones into a matrix of zeros and ones numbers, simply subtract '0' from the string.
This may be what you're looking for:
M = dec2bin(rand(10, 1) * 2^32);
M = M - '0'; %convert M into an array of numbers 0 or 1
[m, n] = size(M);
M2 = [zeros(m, 3*ceil(n/3)-n), M];
X = xor(xor(M2(:, 1:3:end-2), M2(:, 2:3:end-1)), M2(:, 3:3:end))
it works fine... thanks a lot....

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More Answers (2)

Jan
Jan on 9 Nov 2014
Edited: Jan on 9 Nov 2014
s = dec2bin(rand(50,1)*2^32);
t = repmat(' ', size(s, 1), size(s, 2) * 2 - 1);
t(:, 1:2:end) = s;

2 Comments

i'm writing an algorithm to calculate CA rule 150 from this sequence, so when i try these codes didn't give the right answer, this is my code:
M = dec2bin(rand(10,1)*2^32);
[m,n] = size(t);
M2 = [zeros(m,3*ceil(n/3)-n),t];
X = xor(xor(M2(:,1:3:end-2),M2(:,2:3:end-1)),M2(:,3:3:end))
if : M = [0 0 0 1 1 1 1 1 1 0 1 1 1 0 1 0 0 0 0 0 0 1 1 0 1 0 0 1 0 1 1 1]
then X = 0 0 1 0 0 1 0 0 1 1 1
so how to make it run?
Guillaume
Guillaume on 9 Nov 2014
Edited: Guillaume on 9 Nov 2014
I don't know what CA rule 150 is so why don't you explain it.
It is now clear however, that your original question is a case of xy problem. Looking at your attempted code, you don't need to insert spaces and actually want to operate on numbers rather than strings.
xor certainly does not work with strings.
See comment on my own answer for a possible solution.

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yonatan gerufi
yonatan gerufi on 9 Nov 2014
see in the "file exchange" :

3 Comments

it did not run for this issue.if i have matrix as (1110) i want to add one space between the element of it (1 1 1 0) so i want to modify this code if its possible
dec2bin(rand(50,1)*2^32)
so it can add the space automatically.
perhaps i misunderstood you.
the code : dec2bin(rand(50,1)*2^32)
gives you string of ones & zeros. you can pad it with ' ' (space), and then you will have space between the elements.
It gives a 2D character array, not a simple string. I think maybe he wants all those rows concatenated together with a space in between them.

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