# Convert vector loop to matrix loop

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There is a loop for working with a vector, can it be made to work with a matrix?

z=zeros(100,900); %

x=z(:,1);

y=x;

j=1;

i=1;

u=1;

c=rand(1,900);

for i=1:100

j=j+1;

x(j)=x(i)+0.4*cos(20)/0.226*pi+c(1);

% in the c(1) loop this is because the loop is for the first column,

% in the matrix loop it should be c(num)

u=u+1

y(u)=y(i)+0.64*sin(78)/x(i)*pi+c(1);

end

I will be glad to any advice

##### 4 Comments

KSSV
on 22 Feb 2022

### Accepted Answer

DGM
on 22 Feb 2022

Edited: DGM
on 22 Feb 2022

You mean like this?

c = rand(1,900);

x = zeros(100,900);

y = x;

for k = 1:99

x(k+1,:) = x(k,:) + 0.4*cos(20)/0.226*pi + c;

y(k+1,:) = y(k,:) + 0.64*sin(78)./x(k,:)*pi + c;

end

... but I should ask how you say it's working when it's clearly dividing by zero and creating an entire array of Infs

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