Create a long rectangular signal with a function handle

I was wondering if there is a quick way to create a rectangular signal during 20 sec for example, with a function handle. I tried the following command which requires you to do it for every step.

Thanks.

u=@(t) double((0<=t & t<0.5) + ...
              (1<=t & t<1.5) + ...
              (2<=t & t<2.5)) .* 1;

Answer 1

[Bruno Luong]

myfun = @(t) mod(t,1)<=0.5;
ezplot(myfun, 0, 20)

[AEW]

Thanks!

What about you make it bidirectional as follows?

U=@(t) double((0<=t & t<0.25) - (.5<=t & t<.75) + ...
              (1<=t & t<1.25) - (1.5<=t & t<1.75) + ...
              (2<=t & t<2.25) - (2.5<=t & t<2.75) + ...
              (3<=t & t<3.25) - (3.5<=t & t<3.75) + ...
              (4<=t & t<4.25) - (4.5<=t & t<4.75)) .* 1;

[Bruno Luong]

fun=@(x) interp1(0:0.25:1,[1 0 -1 0 1],mod(x,1),'previous');
ezplot(fun,0,3)

[Bruno Luong]

fun=@(x) ppval(mkpp(0:0.25:1,[1; 0; -1; 0]),mod(x,1))

fun = function_handle with value:
    @(x)ppval(mkpp(0:0.25:1,[1;0;-1;0]),mod(x,1))

ezplot(fun,0,3)

[AEW]

Thanks a lot!

Answer 2

[Sam Chak]

@AEW

Second opinion!

fcn = @(t) (sign(sin(2*pi*t)) + 1)/2;
ezplot(fcn, 0, 5)

[AEW]

Thanks!