Failure in initial objective function evaluation. FSOLVE cannot continue.
Show older comments
i set two files as main.m and root.m.
Here are my codes.
When I runs main.m,it keeps telling me that "Failure in initial objective function evaluation. FSOLVE cannot continue."
Hope someone can help me with that.Thanks!
[main.m]
clear all; clc
fun = @root;
x0 = [2e-5,0.04,0.1524,1.0194,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0];
x = fsolve(fun,x0)
[root.m]
global Tinlet Treact T0
Tinlet = 273+25 ;%K
Treact = 273+150 ;%K
T0 = 273+25;%K
global ki1 ki2 kp11 kp12 kp21 kp22 ktal kd ki10 kp110 kp120 kp210 kp220 ktal0 kd0 Eki1 Ekp11 Ekp12 Ekp21 Ekp22 Ektal Ekd R
R = 8.314;
ki10 = 13.0;
Eki1 = 10000;
ki1 = ki10 * exp(-Eki1*(1/Treact-1/T0));
ki2 = 0.0;
kp110 = 3.70e+05;
Ekp11 = 10000;
kp11 = kp110 * exp(-Ekp11*(1/Treact-1/T0));
kp120 = 673;
Ekp12 = 10000;
kp12 = kp120 * exp(-Ekp12*(1/Treact-1/T0));
kp210 = 1.36e+03;
Ekp21 = 10000;
kp21 = kp210 * exp(-Ekp21*(1/Treact-1/T0));
kp220 = 46 ;
Ekp22 = 10000;
kp22 = kp220 * exp(-Ekp22*(1/Treact-1/T0));
ktal0 = 2.5;
Ektal = 10000;
ktal = ktal0 * exp(-Ektal*(1/Treact-1/T0));
kd0 = 1.0e-04;
Ekd = 10000;
kd = kd0 * exp(-Ekd*(1/Treact-1/T0));
function F = fun(x)
F(1) =ktx(2)*x(5)+x(6)*x(2)-ki1*x(1)*x(3)-ki2*x(1)*x(4)-x(14);
F(2) =UDSI0 - x(14)*stoptime-x(1);
F(3) =ktx(2)*x(2)*(x(6)+x(7))-x(15);
F(4) =UDSI1 - x(15)*stoptime-x(2);
F(5) =(ki1*x(1)+kp11*x(5)+kp21*x(6))*x(3)-x(16);
F(6) =UDSI2 - x(16)*stoptime-x(3);
F(7) =(ki2*x(1)+kp12*x(5)+kp22*x(6))*x(4)-x(17);
F(8) =UDSI3 - x(17)*stoptime-x(4);
F(9) =ki1*x(1)*x(3)+kp21*x(6)*x(3)-kp12*x(5)*x(4)-(ktx(2)*x(2)+kd)*x(5)-x(18);
F(10) =UDSI4 - x(18)*stoptime-x(5);
F(11) =ki2*x(1)*x(4)+kp12*x(5)*x(4)-kp21*x(6)*x(3)-(ktx(2)*x(2)+kd)*x(6)-x(19);
F(12) =UDSI5 - x(19)*stoptime-x(6);
F(13) =ki1*x(1)*x(3)+kp11*x(5)*x(3)+kp21*(x(7)+x(6))*x(3)-kp12*x(7)*x(4)-(ktx(2)*x(2)+kd)*x(7)-x(20);
F(14) =UDSI6 - x(20)*stoptime-x(7);
F(15) =ki2*x(1)*x(4)+kp22*x(6)*x(4)+kp12*(first_lamada2+x(5))*x(4)-kp21*x(7)*x(3)-(ktx(2)*x(2)+kd)*first_lamada2-x(21) ;
F(16) =UDSI7 - x(21)*stoptime-x(8);
F(17) =ki1*x(1)*x(3)+kp11*(2*x(7)+x(5))*x(3)+kp21*(x(10)+2*x(8)+x(6))*x(3)-kp12*x(9)*x(4)-(ktx(2)*x(2)+kd)*x(9)-x(22);
F(18) =UDSI8 - x(22)*stoptime-x(9);
F(19) =ki2*x(1)*x(4)+kp22*(2*x(8)+x(6))*x(4)+kp12*(x(9)+2*x(7)+x(5))*x(4)-kp21*x(10)*x(3)-(ktx(2)*x(2)+kd)*x(10)-x(23);
F(20) =UDSI9 - x(23)*stoptime-x(10);
F(21) =(ktx(2)*x(2)+kd)*(x(5)+x(6))-x(24);
F(22) =UDSI10 - x(24)*stoptime-x(11);
F(23) =(ktx(2)*x(2)+kd)*(x(7)+x(8))-x(25);
F(24) =UDSI11 - x(25)*stoptime-x(12);
F(25) =(ktx(2)*x(2)+kd)*(x(9)+x(10))-x(26);
F(26) =UDSI12 - x(25)*stoptime-x(13);
F = [F(1),F(2),F(3),F(4),F(5),F(6),F(7),F(8),F(9),F(10),F(11),F(12),F(13),F(14),F(15),F(16),F(17),F(18),F(19),F(20),F(21),F(22),F(23),F(24),F(25),F(26)];
end
Accepted Answer
More Answers (1)
ma xueyi
on 30 Apr 2022
0 votes
Categories
Find more on Programming in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!